Answered

Identify the correct mole ratio for each substance.

Sodium chloride (NaCl)
[tex]\[ \text{Na} : \text{Cl} = 1: \square \][/tex]

Ammonium nitrate (NH[tex]\(_4\)[/tex]NO[tex]\(_3\)[/tex])
[tex]\[ \text{H} : \text{O} = 4: \square \][/tex]



Answer :

To determine the mole ratios for the given compounds, let's analyze each one in detail.

### Sodium chloride (NaCl)
- The chemical formula for sodium chloride is NaCl.
- This formula indicates that each molecule of sodium chloride is composed of one sodium (Na) atom and one chlorine (Cl) atom.

Thus, the mole ratio for sodium (Na) to chlorine (Cl) in sodium chloride (NaCl) is:

[tex]\[ \text{Na} : \text{Cl} = 1 : 1 \][/tex]

### Ammonium nitrate (NH_4NO_3)
- The chemical formula for ammonium nitrate is [tex]\( \text{NH}_4\text{NO}_3 \)[/tex].
- Each molecule of ammonium nitrate contains one ammonium ion ([tex]\( \text{NH}_4^+ \)[/tex]) and one nitrate ion ([tex]\( \text{NO}_3^- \)[/tex]).
- The ammonium ion ([tex]\( \text{NH}_4^+ \)[/tex]) consists of 1 nitrogen (N) atom and 4 hydrogen (H) atoms.
- The nitrate ion ([tex]\( \text{NO}_3^- \)[/tex]) consists of 1 nitrogen (N) atom and 3 oxygen (O) atoms.

From the ammonium ion, we have 4 hydrogen (H) atoms.
From the nitrate ion, we have 3 oxygen (O) atoms.

Thus, the mole ratio for hydrogen (H) to oxygen (O) in ammonium nitrate (NH_4NO_3) is:

[tex]\[ \text{H} : \text{O} = 4 : 3 \][/tex]

Putting it all together:

- For sodium chloride ([tex]\( \text{NaCl} \)[/tex]), the mole ratio of Na to Cl is [tex]\( 1 : 1 \)[/tex].
- For ammonium nitrate ([tex]\( \text{NH}_4\text{NO}_3 \)[/tex]), the mole ratio of H to O is [tex]\( 4 : 3 \)[/tex].