Factor completely [tex]2x^2 - 2x - 40[/tex].

A. [tex]2(x - 5)(x + 4)[/tex]

B. [tex](2x - 10)(x + 4)[/tex]

C. [tex](x - 5)(2x + 8)[/tex]

D. [tex]2(x - 4)(x + 5)[/tex]



Answer :

To factor the quadratic expression [tex]\(2x^2 - 2x - 40\)[/tex] completely, follow these steps:

1. Identify the Greatest Common Factor (GCF):
Observe that each term in [tex]\(2x^2 - 2x - 40\)[/tex] has a factor of 2. Thus, the GCF is 2. Factor out the GCF:
[tex]\[ 2x^2 - 2x - 40 = 2(x^2 - x - 20) \][/tex]

2. Factor the quadratic expression [tex]\(x^2 - x - 20\)[/tex]:
We need to find two numbers that multiply to [tex]\(-20\)[/tex] (the constant term) and add to [tex]\(-1\)[/tex] (the coefficient of the linear term, [tex]\(x\)[/tex]).

3. Find the factors:
Consider the pairs of factors of [tex]\(-20\)[/tex]:
[tex]\[ (-1, 20), (1, -20), (-2, 10), (2, -10), (-4, 5), (4, -5) \][/tex]
We find that [tex]\((4, -5)\)[/tex] are the numbers that multiply to [tex]\(-20\)[/tex] and add to [tex]\(-1\)[/tex]:
[tex]\[ 4 + (-5) = -1 \][/tex]

4. Rewrite the quadratic expression using these factors:
[tex]\[ x^2 - x - 20 = (x + 4)(x - 5) \][/tex]
Therefore, substituting back in the expression, we have:
[tex]\[ 2(x^2 - x - 20) = 2(x + 4)(x - 5) \][/tex]

5. Verify the chosen factors are correct:
Multiply the factors to ensure correctness:
[tex]\[ (x + 4)(x - 5) = x^2 - 5x + 4x - 20 = x^2 - x - 20 \][/tex]
So, the factorization is verified.

Therefore, the completely factored form of the expression [tex]\(2x^2 - 2x - 40\)[/tex] is:
[tex]\[ 2(x - 5)(x + 4) \][/tex]

The correctly chosen answer is:
[tex]\[ 2(x - 5)(x + 4) \][/tex]

Thus, the answer is [tex]\(2(x - 5)(x + 4)\)[/tex].