Answer :
Answer:
Explanation:
To find the percentage of barium in the compound, we can follow these steps:
Calculate moles of BaSO4 formed:
From the given data, 0.1060 g of BaSO4 was formed.
Molar mass of BaSO4=137.33 g/mol (Ba)+32.06 g/mol (S)+4×16.00 g/mol (O)=233.39 g/mol
Molar mass of BaSO4=137.33g/mol (Ba)+32.06g/mol (S)+4×16.00g/mol (O)=233.39g/mol
Number of moles of BaSO4 formed:
moles of BaSO4=0.1060 g233.39 g/mol=0.000454 mol
moles of BaSO4=233.39g/mol0.1060g=0.000454mol
Determine moles of Ba in BaSO4:
According to the balanced chemical equation for the reaction:
Ba2++SO42−→BaSO4
Ba2++SO42−→BaSO4
1 mole of BaSO4 contains 1 mole of Ba.
moles of Ba=0.000454 mol
moles of Ba=0.000454mol
Calculate the mass of Ba in the sample:
Now, we find the mass of Ba in the sample that produced BaSO4:
mass of Ba=moles of Ba×molar mass of Ba=0.000454 mol×137.33 g/mol=0.0623 g
mass of Ba=moles of Ba×molar mass of Ba=0.000454mol×137.33g/mol=0.0623g
Calculate the percentage of Ba in the compound:
Finally, the percentage of Ba in the compound is:
Percentage of Ba=(mass of Bamass of sample)×100%mass of sample=0.2680 g(given)Percentage of Ba=(0.0623 g0.2680 g)×100%=23.25%
Percentage of Ba=(mass of samplemass of Ba)×100%mass of sample=0.2680g(given)Percentage of Ba=(0.2680g0.0623g)×100%=23.25%
Therefore, the percentage of barium in the compound is ( \boxed{
