Let's analyze the boiling points of the given substances: hydrogen (H₂), fluorine (F₂), and hydrogen fluoride (HF).
1. Given Boiling Points:
- The boiling point of hydrogen (H₂) is 20.28 Kelvin.
- The boiling point of fluorine (F₂) is 85.03 Kelvin.
- The boiling point of hydrogen fluoride (HF) is given as 19.5 degrees Celsius. First, we need to convert this temperature to Kelvin.
2. Conversion of Celsius to Kelvin:
[tex]\[
\text{Boiling point of HF in Kelvin} = 19.5 + 273.15 = 292.65 \text{ K}
\][/tex]
3. Comparison with Hydrogen (H₂):
- Boiling point of HF is 292.65 K.
- Boiling point of H₂ is 20.28 K.
Clearly, 292.65 K (HF) is greater than 20.28 K (H₂).
4. Comparison with Fluorine (F₂):
- Boiling point of HF is 292.65 K.
- Boiling point of F₂ is 85.03 K.
Clearly, 292.65 K (HF) is greater than 85.03 K (F₂).
Therefore, the boiling point of HF is greater than the boiling point of H₂, and it is greater than the boiling point of F₂.
To summarize:
The boiling point of HF is greater than the boiling point of H₂, and it is greater than the boiling point of F₂.
