Given the algebraic expression [tex]\left(27 x^{\frac{5}{3}}\right)^{-\frac{1}{3}}[/tex], create an equivalent expression.

A. [tex]\frac{1}{3 x^{\frac{5}{9}}}[/tex]

B. [tex]\frac{1}{3 x^{\frac{4}{3}}}[/tex]

C. [tex]3 x^{\frac{5}{9}}[/tex]

D. [tex]3 x^{\frac{4}{3}}[/tex]



Answer :

Let's simplify the algebraic expression [tex]\(\left(27 x^{\frac{5}{3}}\right)^{-\frac{1}{3}}\)[/tex].

1. Exponentiation Properties:
We start with the given expression
[tex]\[ \left(27 x^{\frac{5}{3}}\right)^{-\frac{1}{3}} \][/tex]
According to the exponentiation properties, we can apply the exponent [tex]\(-\frac{1}{3}\)[/tex] to both the constant [tex]\(27\)[/tex] and the [tex]\(x^{\frac{5}{3}}\)[/tex] term separately.

2. Simplifying the Constant Term:
The term [tex]\(27\)[/tex] can be rewritten as [tex]\(3^3\)[/tex]:
[tex]\[ 27 = 3^3 \][/tex]
Now apply the exponent:
[tex]\[ (3^3)^{-\frac{1}{3}} = 3^{3 \cdot -\frac{1}{3}} = 3^{-1} = \frac{1}{3} \][/tex]

3. Simplifying the Variable Term:
Now let's handle [tex]\(x^{\frac{5}{3}}\)[/tex] raised to the power of [tex]\(-\frac{1}{3}\)[/tex]:
[tex]\[ \left(x^{\frac{5}{3}}\right)^{-\frac{1}{3}} = x^{\frac{5}{3} \cdot -\frac{1}{3}} = x^{-\frac{5}{9}} \][/tex]

4. Combining the Results:
Combining the simplified constant and variable parts gives us:
[tex]\[ \frac{1}{3} \cdot x^{-\frac{5}{9}} = \frac{1}{3 x^{\frac{5}{9}}} \][/tex]

Thus, the algebraic expression [tex]\(\left(27 x^{\frac{5}{3}}\right)^{-\frac{1}{3}}\)[/tex] simplifies to:
[tex]\[ \boxed{\frac{1}{3 x^{\frac{5}{9}}}} \][/tex]

This matches the first choice in the given list.