Let's analyze the genetic cross step-by-step to determine the phenotypes and their respective fractions for the offspring.
1. Parental Genotypes and Traits:
- The first parent has the genotype BBEE. This parent has:
- Black Fur (dominant allele B)
- Black Eyes (dominant allele E)
- The second parent has the genotype bbee. This parent has:
- White Fur (recessive allele b)
- Red Eyes (recessive allele e)
2. Possible Gametes:
- BBEE can only produce gametes with BE.
- bbee can only produce gametes with be.
3. Crossing the Gametes:
- When BE from the first parent is crossed with be from the second parent, the genotype of the offspring will be:
- BbEe
4. Determining the Phenotype for BbEe:
- B (Black Fur) is dominant over b (White Fur).
- E (Black Eyes) is dominant over e (Red Eyes).
- Therefore, the offspring with the genotype BbEe will exhibit:
- Black Fur (due to the presence of at least one dominant B)
- Black Eyes (due to the presence of at least one dominant E)
5. Predicted Fraction for Each Phenotype:
- As all offspring have the same genotype BbEe, they all have the same phenotype, which is Black Fur and Black Eyes.
Thus, the predicted fractions for each phenotype are:
| Phenotype | Predicted Fraction |
|----------------------------|--------------------|
| Black Fur and Black Eyes | 1.0 |
| Black Fur and Red Eyes | 0.0 |
| White Fur and Black Eyes | 0.0 |
| White Fur and Red Eyes | 0.0 |
Now, filling in the data table:
[tex]\[
\begin{tabular}{|l|c|c|c|c|}
\cline { 2 - 5 }
& \begin{tabular}{c} Black Fur and \\ Black Eyes \end{tabular}
& \begin{tabular}{c} Black Fur and \\ Red Eyes \end{tabular}
& \begin{tabular}{c} White Fur and \\ Black Eyes \end{tabular}
& \begin{tabular}{c} White Fur and \\ Red Eyes \end{tabular} \\
\hline
Predicted Fraction & 1.0 & 0.0 & 0.0 & 0.0 \\
\hline
\end{tabular}
\][/tex]
So, the offspring will all have Black Fur and Black Eyes with a fraction of 1.0, and the other phenotypes will have a fraction of 0.0.
