Answer :
Certainly! Let's delve into the effects of the changes on each electric quantity:
\begin{tabular}{|l|l|l|l|}
\hline
\multicolumn{1}{|c|}{Change} & \begin{tabular}{c}
Effect on \\
electric force
\end{tabular} & \begin{tabular}{c}
Effect on \\
electric \\
potential energy
\end{tabular} & \begin{tabular}{l}
Effect on \\
potential \\
difference
\end{tabular} \\
\hline
\begin{tabular}{l}
Multiply one \\
charge by 2
\end{tabular} & \begin{tabular}{c}
The electric force between \\
two charges, according to \\
Coulomb's law, is directly \\
proportional to the product \\
of the two charges. If you \\
multiply one charge by 2, \\
the electric force will also \\
be multiplied by 2.
\end{tabular} & \begin{tabular}{c}
The electric potential \\
energy is also directly \\
proportional to the product \\
of the two charges. Thus, \\
multiplying one charge by \\
2 will double the electric \\
potential energy.
\end{tabular} & \begin{tabular}{c}
The electric potential \\
difference, which is the \\
work done per unit charge \\
to move a test charge \\
from one point to another, \\
will be doubled as well \\
when one charge is \\
multiplied by 2.
\end{tabular} \\
\hline
\begin{tabular}{l}
Multiply distance \\
by 2
\end{tabular} & \begin{tabular}{c}
According to Coulomb's law, \\
the electric force is \\
inversely proportional to \\
the square of the distance \\
between the charges. \\
If the distance is doubled, \\
the electric force will be \\
reduced by a factor of 4.
\end{tabular} & \begin{tabular}{c}
The electric potential energy \\
is inversely proportional to \\
the distance between the \\
charges. Hence, doubling \\
the distance will halve the \\
electric potential energy.
\end{tabular} & \begin{tabular}{c}
The electric potential \\
difference is also inversely \\
proportional to the distance \\
between the charges. \\
Doubling the distance will \\
therefore halve the \\
potential difference.
\end{tabular} \\
\hline
\end{tabular}
This table captures the effects of multiplying one charge by 2 and multiplying the distance between two charged particles by 2 on electric force, electric potential energy, and electric potential difference.
\begin{tabular}{|l|l|l|l|}
\hline
\multicolumn{1}{|c|}{Change} & \begin{tabular}{c}
Effect on \\
electric force
\end{tabular} & \begin{tabular}{c}
Effect on \\
electric \\
potential energy
\end{tabular} & \begin{tabular}{l}
Effect on \\
potential \\
difference
\end{tabular} \\
\hline
\begin{tabular}{l}
Multiply one \\
charge by 2
\end{tabular} & \begin{tabular}{c}
The electric force between \\
two charges, according to \\
Coulomb's law, is directly \\
proportional to the product \\
of the two charges. If you \\
multiply one charge by 2, \\
the electric force will also \\
be multiplied by 2.
\end{tabular} & \begin{tabular}{c}
The electric potential \\
energy is also directly \\
proportional to the product \\
of the two charges. Thus, \\
multiplying one charge by \\
2 will double the electric \\
potential energy.
\end{tabular} & \begin{tabular}{c}
The electric potential \\
difference, which is the \\
work done per unit charge \\
to move a test charge \\
from one point to another, \\
will be doubled as well \\
when one charge is \\
multiplied by 2.
\end{tabular} \\
\hline
\begin{tabular}{l}
Multiply distance \\
by 2
\end{tabular} & \begin{tabular}{c}
According to Coulomb's law, \\
the electric force is \\
inversely proportional to \\
the square of the distance \\
between the charges. \\
If the distance is doubled, \\
the electric force will be \\
reduced by a factor of 4.
\end{tabular} & \begin{tabular}{c}
The electric potential energy \\
is inversely proportional to \\
the distance between the \\
charges. Hence, doubling \\
the distance will halve the \\
electric potential energy.
\end{tabular} & \begin{tabular}{c}
The electric potential \\
difference is also inversely \\
proportional to the distance \\
between the charges. \\
Doubling the distance will \\
therefore halve the \\
potential difference.
\end{tabular} \\
\hline
\end{tabular}
This table captures the effects of multiplying one charge by 2 and multiplying the distance between two charged particles by 2 on electric force, electric potential energy, and electric potential difference.