In any solution in water at [tex]$25^{\circ} C$[/tex], the ion product constant of water [tex]$\left( K _w\right)=\left[ H _3 O ^{+}\right][ OH ^{-}] = 1 \times 10^{-14}$[/tex].

(A) True
(B) False



Answer :

Let's address the given statement about the ion product constant of water at [tex]$25^{\circ} C$[/tex].

### Important Background Information:
The ion product constant of water (denoted as [tex]\( K_w \)[/tex]) at [tex]$25^{\circ} C$[/tex] is a well-known property and is crucial in understanding the self-ionization of water. The formula for [tex]\( K_w \)[/tex] is:

[tex]\[ K_w = [H_3O^+][OH^-] \][/tex]

### Recognized Value:
For pure water at [tex]$25^{\circ} C$[/tex], the product of the molar concentrations of hydronium ions ([tex]\([H_3O^+]\)[/tex]) and hydroxide ions ([tex]\([OH^-]\)[/tex]) is always:

[tex]\[ K_w = 1 \times 10^{-14} \][/tex]

This value holds true regardless of whether the solution is acidic, neutral, or basic as long as it is at [tex]$25^{\circ} C$[/tex].

### Given Statement:
The given statement claims:

[tex]\[ K_w = [H_3O^+][OH^-] = 1 \times 10^{-7} \][/tex]

### Verification:
- To verify whether this statement is true, compare the given value for [tex]\( K_w \)[/tex] with the well-established value of [tex]\( K_w \)[/tex] at [tex]$25^{\circ} C$[/tex].
- The correct value of [tex]\( K_w \)[/tex] is [tex]\( 1 \times 10^{-14} \)[/tex], which is substantially different from [tex]\( 1 \times 10^{-7} \)[/tex].

### Conclusion:
Since the given statement suggests that [tex]\( K_w = 1 \times 10^{-7} \)[/tex], which is incorrect (the correct value being [tex]\( 1 \times 10^{-14} \)[/tex]), we conclude that the given statement is false.

Thus, the answer to the given question is:

(B) False.