To determine how many moles of KOH react with 1 mole of MgCl₂, we need to look at the balanced chemical equation:
[tex]\[ \text{MgCl}_2 + 2 \text{KOH} \rightarrow \text{Mg(OH)}_2 + 2 \text{KCl} \][/tex]
From the balanced equation, we can observe the stoichiometric coefficients in front of each reactant and product. These coefficients indicate the proportion in which the substances react and are produced.
- 1 mole of MgCl₂ reacts with 2 moles of KOH,
- Producing 1 mole of Mg(OH)₂ and 2 moles of KCl.
Therefore, according to the stoichiometric proportions of the reaction, 1 mole of MgCl₂ reacts with 2 moles of KOH.
Given the question and these observations, the correct answer is:
C. 2
