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A plumber charges [tex]$\$[/tex]130[tex]$ to start a job plus $[/tex]\[tex]$56$[/tex] per hour. How many hours did she work if the total bill is [tex]$\$[/tex]214[tex]$?

This problem can be modeled with this equation:
\[
130 + 56x = 214
\]

Step 1: Which operation should be performed to isolate the variable term?
Apply the subtraction property of equality.

Which value do you need to subtract? $[/tex]\qquad 130 \checkmark[tex]$

Step 2: Which operation should be performed to make the coefficient of $[/tex]x$ equal to 1?
Apply the division property of equality.



Answer :

GinnyAnswer
Using the given equation:

[tex]\[ 130 + 56x = 214 \][/tex]

Let's go through the problem step by step:

Step 1: Isolate the variable term

To isolate the term [tex]\( 56x \)[/tex], we first need to remove the constant term on the left side of the equation. We do this by subtracting 130 from both sides of the equation.

[tex]\[ 130 + 56x - 130 = 214 - 130 \][/tex]

This simplifies to:

[tex]\[ 56x = 84 \][/tex]

Step 2: Solve for [tex]\( x \)[/tex]

To isolate [tex]\( x \)[/tex], we need to eliminate the coefficient 56 by dividing both sides of the equation by 56:

[tex]\[ \frac{56x}{56} = \frac{84}{56} \][/tex]

Simplifying the right side, we get:

[tex]\[ x = 1.5 \][/tex]

So, the plumber worked 1.5 hours.

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