What would the answer to the following conversion problem be?
[tex]$96 \, \text{ft} \times \frac{1 \, \text{yd}}{3 \, \text{ft}}$[/tex]
A. [tex]$\frac{32 \, \text{ft}}{1 \, \text{yd}}$[/tex]
B. 32 yd
C. 32 ft
D. [tex][tex]$\frac{32 \, \text{yd}}{1 \, \text{ft}}$[/tex][/tex]