Answer :
To solve the given system of linear equations using determinants, we can employ Cramer's Rule. The system of equations is:
[tex]\[ \begin{array}{l} -3x + 2y = -9 \\ 4x - 15y = -25 \end{array} \][/tex]
According to Cramer's Rule, we solve for [tex]\(x\)[/tex] and [tex]\(y\)[/tex] using the following determinants:
1. Determinant of the Coefficient Matrix ([tex]\(|A|\)[/tex]):
[tex]\[ |A| = \left|\begin{array}{cc} -3 & 2 \\ 4 & -15 \end{array}\right| \][/tex]
2. Determinant of the Matrix for [tex]\(x\)[/tex] ([tex]\(|A_x|\)[/tex]):
[tex]\[ |A_x| = \left|\begin{array}{cc} -9 & 2 \\ -25 & -15 \end{array}\right| \][/tex]
3. Determinant of the Matrix for [tex]\(y\)[/tex] ([tex]\(|A_y|\)[/tex]):
[tex]\[ |A_y| = \left|\begin{array}{cc} -3 & -9 \\ 4 & -25 \end{array}\right| \][/tex]
Using the determinant values you provided:
[tex]\[ |A| = 37.000000000000014 \][/tex]
[tex]\[ |A_x| = 184.99999999999991 \][/tex]
[tex]\[ |A_y| = 110.99999999999997 \][/tex]
We can now form the equations for [tex]\(x\)[/tex] and [tex]\(y\)[/tex] using Cramer's Rule:
[tex]\[ x = \frac{|A_x|}{|A|} \][/tex]
[tex]\[ y = \frac{|A_y|}{|A|} \][/tex]
Substituting the calculated determinants:
[tex]\[ x = \frac{184.99999999999991}{37.000000000000014} \][/tex]
[tex]\[ y = \frac{110.99999999999997}{37.000000000000014} \][/tex]
Upon simplifying these fractions, we get:
[tex]\[ x \approx 5 \][/tex]
[tex]\[ y \approx 3 \][/tex]
Therefore, the determinants that can be used to solve for [tex]\(x\)[/tex] and [tex]\(y\)[/tex] in this system of linear equations are:
[tex]\[ |A| = \left|\begin{array}{cc} -3 & 2 \\ 4 & -15 \end{array}\right|, \quad |A_x| = \left|\begin{array}{cc} -9 & 2 \\ -25 & -15 \end{array}\right|, \quad |A_y| = \left|\begin{array}{cc} -3 & -9 \\ 4 & -25 \end{array}\right| \][/tex]
[tex]\[ \begin{array}{l} -3x + 2y = -9 \\ 4x - 15y = -25 \end{array} \][/tex]
According to Cramer's Rule, we solve for [tex]\(x\)[/tex] and [tex]\(y\)[/tex] using the following determinants:
1. Determinant of the Coefficient Matrix ([tex]\(|A|\)[/tex]):
[tex]\[ |A| = \left|\begin{array}{cc} -3 & 2 \\ 4 & -15 \end{array}\right| \][/tex]
2. Determinant of the Matrix for [tex]\(x\)[/tex] ([tex]\(|A_x|\)[/tex]):
[tex]\[ |A_x| = \left|\begin{array}{cc} -9 & 2 \\ -25 & -15 \end{array}\right| \][/tex]
3. Determinant of the Matrix for [tex]\(y\)[/tex] ([tex]\(|A_y|\)[/tex]):
[tex]\[ |A_y| = \left|\begin{array}{cc} -3 & -9 \\ 4 & -25 \end{array}\right| \][/tex]
Using the determinant values you provided:
[tex]\[ |A| = 37.000000000000014 \][/tex]
[tex]\[ |A_x| = 184.99999999999991 \][/tex]
[tex]\[ |A_y| = 110.99999999999997 \][/tex]
We can now form the equations for [tex]\(x\)[/tex] and [tex]\(y\)[/tex] using Cramer's Rule:
[tex]\[ x = \frac{|A_x|}{|A|} \][/tex]
[tex]\[ y = \frac{|A_y|}{|A|} \][/tex]
Substituting the calculated determinants:
[tex]\[ x = \frac{184.99999999999991}{37.000000000000014} \][/tex]
[tex]\[ y = \frac{110.99999999999997}{37.000000000000014} \][/tex]
Upon simplifying these fractions, we get:
[tex]\[ x \approx 5 \][/tex]
[tex]\[ y \approx 3 \][/tex]
Therefore, the determinants that can be used to solve for [tex]\(x\)[/tex] and [tex]\(y\)[/tex] in this system of linear equations are:
[tex]\[ |A| = \left|\begin{array}{cc} -3 & 2 \\ 4 & -15 \end{array}\right|, \quad |A_x| = \left|\begin{array}{cc} -9 & 2 \\ -25 & -15 \end{array}\right|, \quad |A_y| = \left|\begin{array}{cc} -3 & -9 \\ 4 & -25 \end{array}\right| \][/tex]