11. What is the solution to the system [tex]y = 4x - 8[/tex] and [tex]y = 4x + 2[/tex]?

A. None of the above
B. [tex](2, 0)[/tex]
C. [tex](0, -8)[/tex]
D. [tex](4, 8)[/tex]



Answer :

To solve the system of equations given by [tex]\( y = 4x - 8 \)[/tex] and [tex]\( y = 4x + 2 \)[/tex], we need to determine if there is a point [tex]\((x, y)\)[/tex] that satisfies both equations simultaneously.

1. Set the equations equal to each other:

Since both equations are equal to [tex]\( y \)[/tex], we can set them equal to each other:
[tex]\[ 4x - 8 = 4x + 2 \][/tex]

2. Simplify the equation:

To find the value of [tex]\( x \)[/tex], we aim to isolate [tex]\( x \)[/tex]. Let's subtract [tex]\( 4x \)[/tex] from both sides of the equation:
[tex]\[ 4x - 4x - 8 = 4x - 4x + 2 \][/tex]
Simplifying both sides, we get:
[tex]\[ -8 = 2 \][/tex]

3. Analyze the result:

The equation [tex]\( -8 = 2 \)[/tex] is a contradiction, meaning it is not true. This indicates that there is no value of [tex]\( x \)[/tex] that will satisfy both equations simultaneously.

Since the simplified result led to a contradiction, there is no solution where both equations intersect.

Therefore, the correct answer is:
[tex]\[ \boxed{\text{None of the above}} \][/tex]