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Solve for x.

[tex]\[ 3x = 6x - 2 \][/tex]




Read the lines from "The Tide Rises, The Tide Falls."

"Darkness settles on roofs and walls,
But the sea, the sea in darkness calls;"

The imagery in these lines evokes a sense of:
A. laziness
B. fear
C. mystery
D. despair



The elements that compose seawater, along with the corresponding percents, are shown in the table. If a sample of seawater contains 55 ml, how many ml of hydrogen are in the sample?

\begin{tabular}{|l|l|}
\hline
\multicolumn{2}{|l|}{Seawater Elements} \\
\hline
Chemical & Percent \\
\hline
Oxygen & [tex]$85.84\%$[/tex] \\
\hline
Hydrogen & [tex]$10.82\%$[/tex] \\
\hline
Chlorine & [tex]$1.94\%$[/tex] \\
\hline
Sodium & [tex]$1.08\%$[/tex] \\
\hline
Magnesium & [tex]$0.13\%$[/tex] \\
\hline
Other elements & [tex]$0.19\%$[/tex] \\
\hline
\end{tabular}

There are [tex]\(\square\)[/tex] ml of hydrogen in the sample.
(Type an integer or a decimal rounded to two decimal places)



Answer :

GinnyAnswer
To find out how many milliliters of hydrogen are in a 55 ml seawater sample, we need to use the percentage provided for hydrogen in the seawater composition. Here's a detailed, step-by-step solution:

1. Identify the given data:
- The volume of the seawater sample: [tex]\( 55 \)[/tex] ml
- The percentage of hydrogen in seawater: [tex]\( 10.824\% \)[/tex]

2. Understand what needs to be calculated:
- We need to determine the volume of hydrogen in the 55 ml sample.

3. Set up the equation:
- Since the percentage represents the proportion of the sample that is hydrogen, we can set up the equation as:
[tex]\[ \text{Hydrogen volume} = \left( \frac{\text{Hydrogen percent}}{100} \right) \times \text{Sample volume} \][/tex]

4. Substitute the given values into the equation:
[tex]\[ \text{Hydrogen volume} = \left( \frac{10.824}{100} \right) \times 55 \][/tex]

5. Perform the calculation:
[tex]\[ \text{Hydrogen volume} = 0.10824 \times 55 = 5.9532 \][/tex]

6. Round the result to two decimal places:
- The volume of hydrogen in the sample is [tex]\( 5.95 \)[/tex] ml.

Therefore, there are [tex]\( \boxed{5.95} \)[/tex] ml of hydrogen in the sample.