Solve for [tex]\( x \)[/tex]:

[tex]\[ 3x = 6x - 2 \][/tex]



Format the following question or task so that it is easier to read.
Fix any grammar or spelling errors.
Remove phrases that are not part of the question.
Do not remove or change LaTeX formatting.
Do not change or remove [tex] [/tex] tags.
If the question is nonsense, rewrite it so that it makes sense.
-----
Factorize:

a) [tex]\[ x^2 + 6x + 5 - 4y - y^2 \][/tex]

Response:



Answer :

To factorize the expression [tex]\( x^2 + 6x + 5 - 4y - y^2 \)[/tex], we need to recognize it in a form where we can apply factoring techniques. Here's how you can do it step by step:

1. Rearrange the Given Expression: Group the terms involving [tex]\( x \)[/tex] and [tex]\( y \)[/tex] together.
[tex]\[ x^2 + 6x + 5 - y^2 - 4y \][/tex]

2. Reorder the Expression for Clarity: Write it as:
[tex]\[ x^2 + 6x + 5 - y^2 - 4y \][/tex]

3. Identify and Factor Quadratic Terms: We can see there are two quadratic expressions here, one in [tex]\( x \)[/tex] and one in [tex]\( y \)[/tex]:

[tex]\[ (x^2 + 6x + 5) - (y^2 + 4y) \][/tex]

4. Complete the Square for Each Quadratic:
- For the quadratic in [tex]\( x \)[/tex]:
[tex]\[ x^2 + 6x + 5 = (x + 3)^2 - 4 \][/tex]
However, directly factoring it, we get:
[tex]\[ x^2 + 6x + 5 = (x + 1)(x + 5) \][/tex]

- For the quadratic in [tex]\( y \)[/tex], to see the usual factor form:
[tex]\[ y^2 + 4y = (y + 2)^2 - 4 \][/tex]
But typically, we know:
[tex]\[ - y^2 - 4y = - (y^2 + 4y + 4 - 4); \][/tex]
Combining, we get:
[tex]\[ - (y + 2 - y); usual factor forms: -(y + 1)(y + 4) \][/tex]

5. Combine Both Expressions via Factoring Sum of two common Statements:

But another Elegant Way:

- Recognize if we can merge overall:
[tex]\[ Simplify and rearrange dynamically the overall addition Common factors like; \;Comparing factor cross form to together start expressions ( x - something -twe y ) Directly merger. Putting these together gives us: The factored form of the given expression is: \[ \boxed{(x - y + 1)(x + y + 5)} \][/tex]