Answer :

Alright, let's break down the given expression step by step:

Given expression:
[tex]\[ \frac{x^p}{x^p + x^q} + \frac{1}{x^{p-q} + 1} \][/tex]

Let's denote the terms individually for clarity:
- Term 1: [tex]\(\frac{x^p}{x^p + x^q}\)[/tex]
- Term 2: [tex]\(\frac{1}{x^{p-q} + 1}\)[/tex]

We'll add these two terms together.

### Step-by-Step Simplification:

Step 1: Simplify each term separately.

- Term 1: [tex]\(\frac{x^p}{x^p + x^q}\)[/tex]

This term is already in its simplest form since it represents a ratio of two expressions.

- Term 2: [tex]\(\frac{1}{x^{p-q} + 1}\)[/tex]

This term is also in its simplest form.

Step 2: Add the two terms together with a common denominator.

To add these two terms, we need a common denominator. The common denominator for these terms would be:
[tex]\[ (x^p + x^q)(x^{p-q} + 1) \][/tex]

Rewrite each fraction with this common denominator:

- Rewrite Term 1 with the common denominator:
[tex]\[ \frac{x^p}{x^p + x^q} = \frac{x^p (x^{p-q} + 1)}{(x^p + x^q)(x^{p-q} + 1)} \][/tex]

- Rewrite Term 2 with the common denominator:
[tex]\[ \frac{1}{x^{p-q} + 1} = \frac{x^p + x^q}{(x^p + x^q)(x^{p-q} + 1)} \][/tex]

Step 3: Combine the two rewritten terms.

Now we add the rewritten terms:
[tex]\[ \frac{x^p (x^{p-q} + 1)}{(x^p + x^q)(x^{p-q} + 1)} + \frac{x^p + x^q}{(x^p + x^q)(x^{p-q} + 1)} \][/tex]

Combine the numerators over the common denominator:
[tex]\[ \frac{x^p (x^{p-q} + 1) + (x^p + x^q)}{(x^p + x^q)(x^{p-q} + 1)} \][/tex]

Step 4: Simplify the combined numerator.

Combine the terms in the numerator:
[tex]\[ x^p (x^{p-q} + 1) + x^p + x^q \][/tex]

Distribute [tex]\(x^p\)[/tex]:
[tex]\[ x^p x^{p-q} + x^p + x^p + x^q = x^{2p-q} + x^p + x^p + x^q \][/tex]

Finally, combine like terms:
[tex]\[ x^{2p-q} + 2x^p + x^q \][/tex]

Therefore, the simplified expression becomes:
[tex]\[ \frac{x^{2p-q} + 2x^p + x^q}{(x^p + x^q)(x^{p-q} + 1)} \][/tex]

The overall simplified form for the given expression is:
[tex]\[ \frac{x^p (x^{p-q} + 1) + x^p + x^q}{(x^p + x^q)(x^{p-q} + 1)} \][/tex]

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