If [tex]\cos (\alpha + \beta) = 0[/tex], then the value of [tex]\cos \left(\frac{\alpha + \beta}{2}\right)[/tex] is equal to:



Answer :

To find the value of [tex]\(\cos \left(\frac{\alpha+\beta}{2}\right)\)[/tex], given that [tex]\(\cos (\alpha+\beta) = 0\)[/tex], we can follow these steps:

1. Recognize the Relationship: First, we need to understand the relationship given by [tex]\(\cos (\alpha+\beta) = 0\)[/tex]. The cosine function is zero when its argument is an odd multiple of [tex]\(\frac{\pi}{2}\)[/tex]:
[tex]\[ \alpha + \beta = \frac{\pi}{2} + k\pi \][/tex]
where [tex]\(k\)[/tex] is any integer.

2. Simplification for Simplicity: Since [tex]\(\cos (\alpha+\beta)\)[/tex] is periodic with period [tex]\(2\pi\)[/tex], we can simplify our calculations by choosing the smallest positive multiple. This means:
[tex]\[ \alpha + \beta = \frac{\pi}{2} \][/tex]

3. Halving the Angle: Now, we need to calculate [tex]\(\cos \left(\frac{\alpha+\beta}{2}\right)\)[/tex]. Substitute the value we have from step 2:
[tex]\[ \frac{\alpha + \beta}{2} = \frac{\frac{\pi}{2}}{2} = \frac{\pi}{4} \][/tex]

4. Calculate the Cosine Value: Finally, compute the cosine of [tex]\(\frac{\pi}{4}\)[/tex]:
[tex]\[ \cos \left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2} \][/tex]

In numerical form, the value of [tex]\(\frac{\sqrt{2}}{2}\)[/tex], which is a commonly known trigonometric value, is approximately:
[tex]\[ 0.7071067811865476 \][/tex]

Therefore, the value of [tex]\(\cos \left(\frac{\alpha + \beta}{2}\right)\)[/tex] is:
[tex]\[ 0.7071067811865476 \][/tex]