Which point is an [tex]$x$[/tex]-intercept of the quadratic function [tex]$f(x)=(x+6)(x-3)$[/tex]?

A. [tex]$(0,-6)$[/tex]
B. [tex]$(6,0)$[/tex]
C. [tex]$(-6,0)$[/tex]
D. [tex]$(3,0)$[/tex]



Answer :

To find the [tex]\(x\)[/tex]-intercepts of the quadratic function [tex]\(f(x) = (x + 6)(x - 3)\)[/tex], we need to determine the values of [tex]\(x\)[/tex] for which [tex]\(f(x) = 0\)[/tex].

Here are the detailed steps:

1. Set the function equal to zero:
[tex]\[ (x + 6)(x - 3) = 0 \][/tex]

2. Apply the zero-product property, which states that if a product of two factors is zero, then at least one of the factors must be zero:
[tex]\[ x + 6 = 0 \quad \text{or} \quad x - 3 = 0 \][/tex]

3. Solve each equation for [tex]\(x\)[/tex]:
[tex]\[ x + 6 = 0 \quad \Rightarrow \quad x = -6 \][/tex]
[tex]\[ x - 3 = 0 \quad \Rightarrow \quad x = 3 \][/tex]

These solutions give us the [tex]\(x\)[/tex]-values of the [tex]\(x\)[/tex]-intercepts. The [tex]\(x\)[/tex]-intercepts are the points where the graph crosses the [tex]\(x\)[/tex]-axis, and their coordinates are:
[tex]\[ (-6, 0) \quad \text{and} \quad (3, 0) \][/tex]

Among the given choices:
- [tex]\((0, -6)\)[/tex]: This point is not an [tex]\(x\)[/tex]-intercept.
- [tex]\((6, 0)\)[/tex]: This point is not an [tex]\(x\)[/tex]-intercept.
- [tex]\((-6, 0)\)[/tex]: This point is an [tex]\(x\)[/tex]-intercept.

Thus, the point [tex]\((-6, 0)\)[/tex] is an [tex]\(x\)[/tex]-intercept of the quadratic function [tex]\(f(x) = (x + 6)(x - 3)\)[/tex].