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Consider function [tex]f[/tex], where [tex]B[/tex] is a real number.
[tex]
f(x)=\tan (Bx)
[/tex]

Complete the statement describing the transformations to function [tex]f[/tex] as the value of [tex]B[/tex] is changed.
As the value of [tex]B[/tex] increases, the period of the function [tex]\square[/tex] and the frequency of the function [tex]\square[/tex]. When the value of [tex]B[/tex] is negative, the graph of the function [tex]\square[/tex].



Answer :

Let's analyze the function [tex]\( f(x) = \tan(Bx) \)[/tex] and describe how the transformations occur as the value of [tex]\( B \)[/tex] changes.

1. Period of the Function:

The period of the tangent function [tex]\( \tan(Bx) \)[/tex] is given by [tex]\( \frac{\pi}{|B|} \)[/tex]. As [tex]\( B \)[/tex] increases, the denominator becomes larger, resulting in a smaller period. Therefore, as the value of [tex]\( B \)[/tex] increases, the period of the function decreases.

2. Frequency of the Function:

The frequency of the function is the reciprocal of the period. Hence, the frequency is given by [tex]\( \frac{|B|}{\pi} \)[/tex]. As [tex]\( B \)[/tex] increases, the frequency becomes larger. Thus, as the value of [tex]\( B \)[/tex] increases, the frequency of the function increases.

3. When [tex]\( B \)[/tex] is Negative:

When [tex]\( B \)[/tex] is negative, the function [tex]\( \tan(Bx) \)[/tex] experiences a reflection over the y-axis because replacing [tex]\( x \)[/tex] with [tex]\( -x \)[/tex] in the function [tex]\( \tan(x) \)[/tex] results in [tex]\( \tan(-x) = -\tan(x) \)[/tex]. Therefore, when the value of [tex]\( B \)[/tex] is negative, the graph of the function is a reflection over the y-axis.

Putting it all together, the completed statement is:

As the value of [tex]\( B \)[/tex] increases, the period of the function decreases and the frequency of the function increases. When the value of [tex]\( B \)[/tex] is negative, the graph of the function is a reflection over the y-axis.