Alright, let's solve the division problem [tex]\( 687 \div 4 \)[/tex] step by step.
1. Divide the first digit:
- [tex]\( 6 \div 4 = 1 \)[/tex] (since 4 fits into 6 one time).
- The quotient digit is 1.
- Calculate the remainder: [tex]\( 6 - 4 = 2 \)[/tex].
2. Bring down the next digit:
- Bring down the 8 next to the 2, making it 28.
3. Divide the result:
- [tex]\( 28 \div 4 = 7 \)[/tex].
- The quotient digit is 7.
- Calculate the remainder: [tex]\( 28 - 28 = 0 \)[/tex].
4. Bring down the next digit:
- Bring down the 7.
5. Divide the result:
- [tex]\( 7 \div 4 = 1 \)[/tex] (since 4 fits into 7 one time).
- The quotient digit is 1.
- Calculate the remainder: [tex]\( 7 - 4 = 3 \)[/tex].
Putting it all together, the complete quotient is 171 and the remainder is 3.
Thus, [tex]\( 687 \div 4 = 171 \)[/tex] with a remainder of [tex]\( 3 \)[/tex], which can be written as [tex]\( 171 \, \text{R} \, 3 \)[/tex].
So, the correct answer is:
171 R3
