4. Which of the following must always be true if [tex] x, y [/tex], and [tex] z [/tex] are negative rational numbers?

A. [tex] x \cdot y \cdot z [/tex] is positive
B. [tex] x - y - z [/tex] is negative
C. [tex] x + y + z [/tex] is positive
D. [tex] x \cdot y \cdot z [/tex] is negative



Answer :

Let's analyze the given statements one by one, using the properties of negative rational numbers:

1. Statement A: [tex]\(x \cdot y \cdot z\)[/tex] is positive

- When you multiply three negative numbers, the result is positive. Multiplying two negative numbers gives a positive result and then multiplying that positive result by another negative number gives a negative result. Therefore, Statement A is incorrect because [tex]\(x \cdot y \cdot z\)[/tex] is not positive when [tex]\(x\)[/tex], [tex]\(y\)[/tex], and [tex]\(z\)[/tex] are negative rational numbers.

2. Statement B: [tex]\(x - y - z\)[/tex] is negative

- Let's explore this: [tex]\(x - y - z\)[/tex]. Given that [tex]\(x\)[/tex], [tex]\(y\)[/tex], and [tex]\(z\)[/tex] are negative, let's assume [tex]\(x = -a\)[/tex], [tex]\(y = -b\)[/tex], and [tex]\(z = -c\)[/tex], where [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] are positive rational numbers.

- Substituting these:
[tex]\[ x - y - z = -a - (-b) - (-c) = -a + b + c \][/tex]

- Since [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] are positive, the expression [tex]\(-a + b + c\)[/tex] can be either negative or positive, depending on the relative sizes of [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex]. Thus, we cannot definitively say that [tex]\(x - y - z\)[/tex] is always negative. Therefore, Statement B is not necessarily true.

3. Statement C: [tex]\(x + y + z\)[/tex] is positive

- For the sum [tex]\(x + y + z\)[/tex], since [tex]\(x\)[/tex], [tex]\(y\)[/tex], and [tex]\(z\)[/tex] are all negative rational numbers, the sum of any three negative numbers is also negative. Therefore, Statement C must be true. This is the correct statement.

4. Statement D: [tex]\(x \cdot y \cdot z\)[/tex] is negative

- As discussed in Statement A, multiplying three negative numbers results in a negative product. Therefore, [tex]\(x \cdot y \cdot z\)[/tex] is indeed negative. Since this statement contradicts Statement A but does not contradict Statement C, we might need to re-evaluate.

After a thorough review, the conclusive statement is:

Out of the given options, the statement that always holds true if [tex]\(x\)[/tex], [tex]\(y\)[/tex], and [tex]\(z\)[/tex] are negative rational numbers is:

C) [tex]\(x + y + z\)[/tex] is always negative.