To determine the number of each type of atom in 4 units of [tex]\( \text{Na}_3\text{PO}_4 \)[/tex], we first need to understand the composition of a single unit:
- In one unit of [tex]\( \text{Na}_3\text{PO}_4 \)[/tex]:
- There are 3 sodium (Na) atoms.
- There is 1 phosphorus (P) atom.
- There are 4 oxygen (O) atoms.
Now, since we are dealing with 4 units of [tex]\( \text{Na}_3\text{PO}_4 \)[/tex], we will multiply the number of each type of atom by 4.
Step-by-step calculation:
1. Sodium (Na) atoms:
- There are 3 sodium atoms in one unit.
- For 4 units, the total number of sodium atoms is [tex]\( 3 \times 4 = 12 \)[/tex].
2. Phosphorus (P) atoms:
- There is 1 phosphorus atom in one unit.
- For 4 units, the total number of phosphorus atoms is [tex]\( 1 \times 4 = 4 \)[/tex].
3. Oxygen (O) atoms:
- There are 4 oxygen atoms in one unit.
- For 4 units, the total number of oxygen atoms is [tex]\( 4 \times 4 = 16 \)[/tex].
So, in [tex]\( 4 \text{Na}_3\text{PO}_4 \)[/tex], there are:
- 12 sodium atoms,
- 4 phosphorus atoms,
- 16 oxygen atoms.
Therefore, the correct answer is:
[tex]\( \text{12 sodium, 4 phosphorus, 16 oxygen} \)[/tex].
