Circuit A:
- Resistance: [tex]20 \Omega[/tex]
- Voltage: 24 V

Circuit B:
- Resistance: [tex]250 \Omega[/tex]
- Voltage: 220 V

Circuit C:
- Resistance: [tex]3 \Omega[/tex]
- Voltage: 6 V

Which order shows decreasing current?
A. A, B, C
B. C, A, B
C. C, B, A



Answer :

To determine the order of the circuits by decreasing current, we need to calculate the current in each circuit using Ohm's Law, which is given by the formula:

[tex]\[ I = \frac{V}{R} \][/tex]

where [tex]\( I \)[/tex] is the current, [tex]\( V \)[/tex] is the voltage, and [tex]\( R \)[/tex] is the resistance.

Step-by-Step Calculation:

1. Calculate the current in Circuit A:
- Resistance ([tex]\( R_A \)[/tex]) = 20 Ω
- Voltage ([tex]\( V_A \)[/tex]) = 24 V

Using Ohm's Law:
[tex]\[ I_A = \frac{V_A}{R_A} = \frac{24 \text{ V}}{20 \text{ Ω}} = 1.2 \text{ A} \][/tex]

2. Calculate the current in Circuit B:
- Resistance ([tex]\( R_B \)[/tex]) = 250 Ω
- Voltage ([tex]\( V_B \)[/tex]) = 220 V

Using Ohm's Law:
[tex]\[ I_B = \frac{V_B}{R_B} = \frac{220 \text{ V}}{250 \text{ Ω}} = 0.88 \text{ A} \][/tex]

3. Calculate the current in Circuit C:
- Resistance ([tex]\( R_C \)[/tex]) = 3 Ω
- Voltage ([tex]\( V_C \)[/tex]) = 6 V

Using Ohm's Law:
[tex]\[ I_C = \frac{V_C}{R_C} = \frac{6 \text{ V}}{3 \text{ Ω}} = 2.0 \text{ A} \][/tex]

Now, we have the currents for each circuit:
- Circuit A: 1.2 A
- Circuit B: 0.88 A
- Circuit C: 2.0 A

Order of currents from highest to lowest:
- Circuit C: 2.0 A
- Circuit A: 1.2 A
- Circuit B: 0.88 A

Therefore, the order that shows decreasing current is:

[tex]\[ \boxed{\text{C, A, B}} \][/tex]