A baseball player hit 55 home runs in a season. Of the 55 home runs, 16 went to right field, 16 went to right center field, 12 went to center field, 10 went to left center field, and 1 went to left field.

(a) What is the probability that a randomly selected home run was hit to right field?

(b) What is the probability that a randomly selected home run was hit to left field?

(c) Was it unusual for this player to hit a home run to left field? Explain.



Answer :

Let's solve each part of the question step-by-step.

### (a) What is the probability that a randomly selected home run was hit to right field?

To find the probability, we use the formula:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]

In this case:
- The number of favorable outcomes (home runs hit to right field) is 16.
- The total number of outcomes (total home runs) is 55.

So, the probability that a randomly selected home run was hit to right field is:
[tex]\[ \text{Probability} = \frac{16}{55} \approx 0.2909 \][/tex]

Therefore, the probability is approximately 0.2909.

### (b) What is the probability that a randomly selected home run was hit to left field?

Using the same probability formula:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]

In this case:
- The number of favorable outcomes (home runs hit to left field) is 1.
- The total number of outcomes (total home runs) is 55.

So, the probability that a randomly selected home run was hit to left field is:
[tex]\[ \text{Probability} = \frac{1}{55} \approx 0.0182 \][/tex]

Therefore, the probability is approximately 0.0182.

### (c) Was it unusual for this player to hit a home run to left field? Explain.

To determine if an event is unusual, we generally consider whether the probability of the event occurring is less than 0.05 (or 5%).

From part (b), we calculated the probability of hitting a home run to left field to be approximately 0.0182.

Since 0.0182 is less than 0.05, it is considered unusual for this player to hit a home run to left field.

Therefore, it was indeed unusual for this player to hit a home run to left field because the probability of such an event is very low (less than 0.05).

In summary:
(a) The probability that a home run was hit to right field is approximately 0.2909.
(b) The probability that a home run was hit to left field is approximately 0.0182.
(c) It was unusual for the player to hit a home run to left field, as the probability of this happening is less than 0.05.