A sum of \[tex]$400 is deposited in an account with a 5.5% interest rate, compounded continuously.

What is the balance after 8 years?

\[
F = \$[/tex][?]
\]



Answer :

To determine the balance of a deposit in an account with continuous compounding interest, we use the continuous compounding formula, which is:

[tex]\[ A = P \cdot e^{rt} \][/tex]

where:
- [tex]\( A \)[/tex] is the amount of money accumulated after [tex]\( n \)[/tex] years, including interest.
- [tex]\( P \)[/tex] is the principal amount (the initial amount of money).
- [tex]\( r \)[/tex] is the annual interest rate (in decimal form).
- [tex]\( t \)[/tex] is the time the money is invested or borrowed for, in years.
- [tex]\( e \)[/tex] is the base of the natural logarithm, approximately equal to 2.71828.

Given:
- The principal amount ([tex]\( P \)[/tex]) is [tex]$400. - The annual interest rate (\( r \)) is 5.5%, which in decimal form is \( 0.055 \). - The time (\( t \)) is 8 years. Next, we can calculate the balance (\( A \)): \[ A = 400 \cdot e^{(0.055 \cdot 8)} \] From the provided continuous compounding formula and given values, we find that when these values are input into the formula, we get: \[ A \approx \$[/tex]621.08 \]

Therefore, the balance after 8 years will be approximately:

[tex]\[ \boxed{\$621.08} \][/tex]