Answer :
Let's analyze the equation of the function given: [tex]\( y = -2x + 1 \)[/tex].
In the slope-intercept form of a linear equation, which is [tex]\( y = mx + b \)[/tex], the slope [tex]\( m \)[/tex] is the coefficient of [tex]\( x \)[/tex], and the [tex]\( y \)[/tex]-intercept [tex]\( b \)[/tex] is the constant term.
1. Identify the slope:
- The equation is in the form [tex]\( y = mx + b \)[/tex].
- Here, the coefficient of [tex]\( x \)[/tex] is [tex]\(-2\)[/tex].
- Thus, the slope [tex]\( m \)[/tex] is [tex]\(-2\)[/tex].
2. Identify the [tex]\( y \)[/tex]-intercept:
- The [tex]\( y \)[/tex]-intercept is the constant term, the value of [tex]\( y \)[/tex] when [tex]\( x = 0 \)[/tex].
- In this equation, the constant term is [tex]\( 1 \)[/tex].
- Therefore, the [tex]\( y \)[/tex]-intercept is the point [tex]\((0, 1)\)[/tex].
Given these calculations:
- The slope is [tex]\(-2\)[/tex].
- The [tex]\( y \)[/tex]-intercept is [tex]\((0, 1)\)[/tex].
Now, let's match these values to the given choices:
A. The slope is -2. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, 1) \)[/tex].
B. The slope is 1. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, -2) \)[/tex].
C. The slope is 1. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, 2) \)[/tex].
D. The slope is 2. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, 1) \)[/tex].
After comparing, we see that option A correctly identifies the slope and y-intercept.
Therefore, the correct answer is:
A. The slope is -2. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, 1) \)[/tex].
In the slope-intercept form of a linear equation, which is [tex]\( y = mx + b \)[/tex], the slope [tex]\( m \)[/tex] is the coefficient of [tex]\( x \)[/tex], and the [tex]\( y \)[/tex]-intercept [tex]\( b \)[/tex] is the constant term.
1. Identify the slope:
- The equation is in the form [tex]\( y = mx + b \)[/tex].
- Here, the coefficient of [tex]\( x \)[/tex] is [tex]\(-2\)[/tex].
- Thus, the slope [tex]\( m \)[/tex] is [tex]\(-2\)[/tex].
2. Identify the [tex]\( y \)[/tex]-intercept:
- The [tex]\( y \)[/tex]-intercept is the constant term, the value of [tex]\( y \)[/tex] when [tex]\( x = 0 \)[/tex].
- In this equation, the constant term is [tex]\( 1 \)[/tex].
- Therefore, the [tex]\( y \)[/tex]-intercept is the point [tex]\((0, 1)\)[/tex].
Given these calculations:
- The slope is [tex]\(-2\)[/tex].
- The [tex]\( y \)[/tex]-intercept is [tex]\((0, 1)\)[/tex].
Now, let's match these values to the given choices:
A. The slope is -2. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, 1) \)[/tex].
B. The slope is 1. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, -2) \)[/tex].
C. The slope is 1. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, 2) \)[/tex].
D. The slope is 2. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, 1) \)[/tex].
After comparing, we see that option A correctly identifies the slope and y-intercept.
Therefore, the correct answer is:
A. The slope is -2. The [tex]\( y \)[/tex]-intercept is [tex]\( (0, 1) \)[/tex].
Answer:
Step-by-step explanation:
The given function is \( y = -2x + 1 \).
Let's identify the slope and the \( y \)-intercept:
1. **Slope:** The slope of a linear function in the form \( y = mx + b \) is represented by \( m \). In this case, \( m = -2 \).
2. **\( y \)-intercept:** The \( y \)-intercept is the point where the graph intersects the \( y \)-axis. It is represented as \( (0, b) \) in the equation \( y = mx + b \). Here, \( b = 1 \).
Therefore, according to the options provided:
A. The slope is \(-2\). The \( y \)-intercept is \((0,1)\).
This matches with the function \( y = -2x + 1 \).
So, the correct answer is \( \boxed{\text{A}} \).