Select the correct equations.

Phil's age is 7 years more than [tex]$\frac{1}{5}$[/tex] times Peter's age. Also, 4 times Phil's age is 2 years less than twice Peter's age. If [tex]$x$[/tex] is Peter's age in years, identify the equation that represents this situation and identify the solution to the equation.

A. [tex]$\frac{1}{5}x + 7 = 2x - 2$[/tex]

B. [tex]$x = 25$[/tex]

C. [tex]$4\left(\frac{1}{5}x + 7\right) = 2x - 2$[/tex]

D. [tex]$4\left(\frac{1}{5}x - 7\right) = 2x - 2$[/tex]

E. [tex]$x = 28$[/tex]

F. [tex]$x = 30$[/tex]



Answer :

Let's begin by defining the variables and translating the problem statement into mathematical equations.

1. Defining the Variables:
Let [tex]\( x \)[/tex] represent Peter's age in years.
Let [tex]\( y \)[/tex] represent Phil's age in years.

2. Translating the Statements:
- Phil's age is 7 years more than [tex]\(\frac{1}{5}\)[/tex] of Peter's age.

Mathematically, this can be written as:
[tex]\[ y = \frac{1}{5} x + 7 \][/tex]

- Four times Phil's age is 2 years less than twice Peter's age.

Mathematically, this can be written as:
[tex]\[ 4y = 2x - 2 \][/tex]

3. Substituting the First Equation into the Second:
We have [tex]\( y \)[/tex] expressed in terms of [tex]\( x \)[/tex] from the first equation:
[tex]\[ y = \frac{1}{5} x + 7 \][/tex]

Substituting [tex]\( y \)[/tex] into the second equation:
[tex]\[ 4\left(\frac{1}{5} x + 7\right) = 2x - 2 \][/tex]

4. Checking the Given Equations:
From the problem, we need to check which of the given equations match this situation.
- The equation [tex]\( 4\left(\frac{1}{5} x + 7\right) = 2x - 2 \)[/tex] matches our derived equation exactly.

Let's simplify it to determine [tex]\( x \)[/tex]:
[tex]\[ 4 \left(\frac{1}{5} x + 7 \right) = 2x - 2 \][/tex]
[tex]\[ \frac{4}{5} x + 28 = 2x - 2 \][/tex]

5. Solving the Equation for [tex]\( x \)[/tex]:
Bring all terms involving [tex]\( x \)[/tex] to one side and constant terms to the other:
[tex]\[ 28 + 2 = 2x - \frac{4}{5} x \][/tex]
[tex]\[ 30 = 2x - \frac{4}{5} x \][/tex]

Combine the [tex]\( x \)[/tex] terms on the right side:
[tex]\[ 30 = \frac{10}{5} x - \frac{4}{5} x \][/tex]
[tex]\[ 30 = \frac{6}{5} x \][/tex]

Solve for [tex]\( x \)[/tex]:
[tex]\[ x = 30 \cdot\frac{5}{6} \][/tex]
[tex]\[ x = 25 \][/tex]

6. Identifying the Correct Answer:
Peter's age [tex]\( x = 25 \)[/tex] satisfies the equation derived from the problem.

7. Conclusion:
The correct equations representing the situation are:
[tex]\[ y = \frac{1}{5} x + 7 \][/tex]
[tex]\[ 4\left(\frac{1}{5} x + 7\right) = 2x - 2 \][/tex]
The solution to the equations is:
[tex]\[ x = 25 \][/tex]

Thus, the correct equations and the correct value of [tex]\( x \)[/tex] are:
- [tex]\( 4\left(\frac{1}{5} x + 7\right) = 2x - 2 \)[/tex]
- [tex]\( x = 25 \)[/tex]