Answer:
a. 60 m
b. -10 m/s²
c. 20 m/s
Explanation:
On a velocity-time graph, the displacement is equal to the area under the curve, and the acceleration is equal to the slope of the curve.
a. From point A to point C, the area under the curve is a trapezoid. Alternatively, we can split this area into a triangle (A to B) and a rectangle (B to C). Using the second method, the displacement is:
x = ½ (2.0 s − 0 s) (20.0 m/s) + (4.0 s − 2.0 s) (20.0 m/s)
x = 60 m
b. From point E to F, the slope of the line is:
a = (20.0 m/s − 40.0 m/s) / (10.0 s − 8.0 s)
a = -10 m/s²
c. From F to G, the velocity is constant at 20 m/s.
