Find the solution to the system of equations.

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[tex]\[
\begin{array}{l}
\left\{
\begin{array}{l}
-7x - 2y = 14 \\
6x + 6y = 18
\end{array}
\right.
\end{array}
\][/tex]

[tex]\[ x = \square \][/tex]

[tex]\[ y = \square \][/tex]



Answer :

Sure, let's solve this system of linear equations step by step.

We are given the system of equations:

[tex]\[ \begin{cases} -7x - 2y = 14 \\ 6x + 6y = 18 \end{cases} \][/tex]

### Step 1: Simplify the Equations if Possible
First, we’ll simplify the second equation:

[tex]\[ 6x + 6y = 18 \][/tex]

Divide every term by 6:

[tex]\[ x + y = 3 \quad \text{(Equation 2)} \][/tex]

### Step 2: Use Substitution or Elimination
We can use the substitution method here. Express [tex]\(y\)[/tex] from Equation 2:

[tex]\[ y = 3 - x \quad \text{(Equation 3)} \][/tex]

### Step 3: Substitute into the First Equation
Now, substitute Equation 3 into the first equation:

[tex]\[ -7x - 2(3 - x) = 14 \][/tex]

Simplify this equation:

[tex]\[ -7x - 6 + 2x = 14 \][/tex]

Combine like terms:

[tex]\[ -5x - 6 = 14 \][/tex]

Add 6 to both sides:

[tex]\[ -5x = 20 \][/tex]

Divide both sides by -5:

[tex]\[ x = -4 \][/tex]

### Step 4: Substitute [tex]\(x\)[/tex] Back into Equation 3
Now, substitute [tex]\(x = -4\)[/tex] back into Equation 3:

[tex]\[ y = 3 - (-4) \][/tex]

Simplify:

[tex]\[ y = 3 + 4 \\ y = 7 \][/tex]

### Step 5: Write the Solution
Therefore, the solution to the system of equations is:

[tex]\[ x = -4 \][/tex]
[tex]\[ y = 7 \][/tex]

We can now fill in the blanks:

[tex]\[ x = -4 \][/tex]
[tex]\[ y = 7 \][/tex]

This means the solution to the system of equations is [tex]\((-4, 7)\)[/tex].