Select the correct answer.

Wanda is a cake designer with a specialty in rectangular silk screen photo cakes. For every cake that she makes, the width of the cake is 4 inches more than the width of the photo in the center of the cake, and the length of every cake is two times its width. The area of the cake Wanda is currently working on is at least 254 square inches.

If [tex]$x$[/tex] represents the width of the photo, which inequality represents this situation?

A. [tex]$x^2+4 x \geq 254$[/tex]
B. [tex]$8 x^2+64 x+128 \geq 254$[/tex]
C. [tex][tex]$2 x^2+16 x+32 \geq 254$[/tex][/tex]
D. [tex]$x^2+8 x+16 \geq 254$[/tex]



Answer :

To determine the correct inequality that represents the situation described:

1. Define Variables:
- Let [tex]\( x \)[/tex] represent the width of the photo (in inches).

2. Width of Cake:
- The width of the cake is 4 inches more than the width of the photo. Therefore, the width of the cake is [tex]\( x + 4 \)[/tex].

3. Length of Cake:
- The length of the cake is two times its width. Thus, the length of the cake is [tex]\( 2(x + 4) \)[/tex].

4. Calculate Area of Cake:
- The area of a rectangle is given by the formula: Area = Length × Width.
- Substituting the expressions for the length and width of the cake, we get:
[tex]\[ \text{Area}_\text{cake} = (x + 4) \times 2(x + 4) \][/tex]

5. Simplify the Expression:
- First, expand the expression:
[tex]\[ \text{Area}_\text{cake} = (x + 4)(2x + 8) \][/tex]

6. Set Up the Inequality:
- We are given that the area of the cake is at least 254 square inches. Therefore, we set up the inequality:
[tex]\[ (x + 4)(2x + 8) \geq 254 \][/tex]

The inequality [tex]\( (x + 4)(2x + 8) \geq 254 \)[/tex] matches option C.

Thus, the correct answer is:
C. [tex]\( 2x^2 + 16x + 32 \geq 254 \)[/tex]