Answer :
To determine what else is produced during the combustion of butane ([tex]\(C_4H_{10}\)[/tex]), let's analyze the provided balanced chemical equation:
[tex]\[ 2 \, C_4H_{10} + 13 \, O_2 \rightarrow 8 \, CO_2 + 10 \, H_2O \][/tex]
The equation indicates that:
- Butane ([tex]\(C_4H_{10}\)[/tex]) reacts with oxygen ([tex]\(O_2\)[/tex]).
- The products of this reaction are carbon dioxide ([tex]\(CO_2\)[/tex]) and water ([tex]\(H_2O\)[/tex]).
We need to identify the substances on the right-hand side of the equation, which represent the products of the reaction.
In the balanced equation:
- [tex]\(8 \, CO_2\)[/tex] indicates that carbon dioxide is produced.
- [tex]\(10 \, H_2O\)[/tex] indicates that water is also produced.
The other substances mentioned in the list of options are:
- [tex]\(C_4H_{10}\)[/tex] (butane), which is a reactant, not a product.
- [tex]\(O_2\)[/tex] (oxygen), which is also a reactant, not a product.
Thus, besides water ([tex]\(H_2O\)[/tex]), carbon dioxide ([tex]\(CO_2\)[/tex]) is also produced during the combustion of butane.
Therefore, the correct answer is: [tex]\(CO_2\)[/tex].
[tex]\[ 2 \, C_4H_{10} + 13 \, O_2 \rightarrow 8 \, CO_2 + 10 \, H_2O \][/tex]
The equation indicates that:
- Butane ([tex]\(C_4H_{10}\)[/tex]) reacts with oxygen ([tex]\(O_2\)[/tex]).
- The products of this reaction are carbon dioxide ([tex]\(CO_2\)[/tex]) and water ([tex]\(H_2O\)[/tex]).
We need to identify the substances on the right-hand side of the equation, which represent the products of the reaction.
In the balanced equation:
- [tex]\(8 \, CO_2\)[/tex] indicates that carbon dioxide is produced.
- [tex]\(10 \, H_2O\)[/tex] indicates that water is also produced.
The other substances mentioned in the list of options are:
- [tex]\(C_4H_{10}\)[/tex] (butane), which is a reactant, not a product.
- [tex]\(O_2\)[/tex] (oxygen), which is also a reactant, not a product.
Thus, besides water ([tex]\(H_2O\)[/tex]), carbon dioxide ([tex]\(CO_2\)[/tex]) is also produced during the combustion of butane.
Therefore, the correct answer is: [tex]\(CO_2\)[/tex].