Certainly! Let's break down the information given in the problem table and fill in as much as we can from the provided results. Here, the results are given in the form:
[tex]\[
\begin{align*}
(5, 1, 4, 3, -1) \\
(4, 2, 8, \text{None}, \text{None}) \\
(3, 3, \text{None}, 5, \text{None}) \\
(2, 4, \text{None}, \text{None}, \text{None}) \\
(1, 5, \text{None}, 10, \text{None})
\end{align*}
\][/tex]
Now, let’s populate the table with this data. Note that "None" indicates missing values that could not be calculated.
[tex]\[
\begin{tabular}{|c|c|c|c|c|c|}
\hline
Trial & \begin{tabular}{c}
Volume of \\
$CuSO_4(\text{mL})$
\end{tabular} & \begin{tabular}{c}
Volume of \\
$Na_2S(\text{mL})$
\end{tabular} &
\begin{tabular}{c}
Mass of Empty \\
Test Tube (g)
\end{tabular} &
\begin{tabular}{c}
Mass of Test Tube and \\
Precipitate (g)
\end{tabular} &
\begin{tabular}{c}
Mass of \\
Precipitate (g)
\end{tabular} \\
\hline
1 & 5 & 1 & 4 & 3 & -1 \\
\hline
2 & 4 & 2 & 8 & \text{None} & \text{None} \\
\hline
3 & 3 & 3 & \text{None} & 5 & \text{None} \\
\hline
4 & 2 & 4 & \text{None} & \text{None} & \text{None} \\
\hline
5 & 1 & 5 & \text{None} & 10 & \text{None} \\
\hline
\end{tabular}
\][/tex]
Here's the detailed step-by-step breakdown:
1. Trial 1:
- Volume of [tex]\( CuSO_4 \)[/tex]: 5 mL
- Volume of [tex]\( Na_2S \)[/tex]: 1 mL
- Mass of Empty Test Tube: 4 g
- Mass of Test Tube and Precipitate: 3 g
- Mass of Precipitate: [tex]\( 3 \text{ g} - 4 \text{ g} = -1 \text{ g} \)[/tex] (indicating a missing or incorrect entry for "Mass of Test Tube and Precipitate")
2. Trial 2:
- Volume of [tex]\( CuSO_4 \)[/tex]: 4 mL
- Volume of [tex]\( Na_2S \)[/tex]: 2 mL
- Mass of Empty Test Tube: 8 g
- Mass of Test Tube and Precipitate: None (no data available)
- Mass of Precipitate: None (cannot be calculated without the mass of the test tube and precipitate)
3. Trial 3:
- Volume of [tex]\( CuSO_4 \)[/tex]: 3 mL
- Volume of [tex]\( Na_2S \)[/tex]: 3 mL
- Mass of Empty Test Tube: None (no data available)
- Mass of Test Tube and Precipitate: 5 g
- Mass of Precipitate: None (cannot be calculated without the mass of the empty test tube)
4. Trial 4:
- Volume of [tex]\( CuSO_4 \)[/tex]: 2 mL
- Volume of [tex]\( Na_2S \)[/tex]: 4 mL
- Mass of Empty Test Tube: None (no data available)
- Mass of Test Tube and Precipitate: None (no data available)
- Mass of Precipitate: None (cannot be calculated without both the mass of the empty test tube and the mass of the test tube and precipitate)
5. Trial 5:
- Volume of [tex]\( CuSO_4 \)[/tex]: 1 mL
- Volume of [tex]\( Na_2S \)[/tex]: 5 mL
- Mass of Empty Test Tube: None (no data available)
- Mass of Test Tube and Precipitate: 10 g
- Mass of Precipitate: None (cannot be calculated without the mass of the empty test tube)
We have now constructed the table with the available data.
