Answer :
Certainly! Let's break down the information given in the problem table and fill in as much as we can from the provided results. Here, the results are given in the form:
[tex]\[ \begin{align*} (5, 1, 4, 3, -1) \\ (4, 2, 8, \text{None}, \text{None}) \\ (3, 3, \text{None}, 5, \text{None}) \\ (2, 4, \text{None}, \text{None}, \text{None}) \\ (1, 5, \text{None}, 10, \text{None}) \end{align*} \][/tex]
Now, let’s populate the table with this data. Note that "None" indicates missing values that could not be calculated.
[tex]\[ \begin{tabular}{|c|c|c|c|c|c|} \hline Trial & \begin{tabular}{c} Volume of \\ $CuSO_4(\text{mL})$ \end{tabular} & \begin{tabular}{c} Volume of \\ $Na_2S(\text{mL})$ \end{tabular} & \begin{tabular}{c} Mass of Empty \\ Test Tube (g) \end{tabular} & \begin{tabular}{c} Mass of Test Tube and \\ Precipitate (g) \end{tabular} & \begin{tabular}{c} Mass of \\ Precipitate (g) \end{tabular} \\ \hline 1 & 5 & 1 & 4 & 3 & -1 \\ \hline 2 & 4 & 2 & 8 & \text{None} & \text{None} \\ \hline 3 & 3 & 3 & \text{None} & 5 & \text{None} \\ \hline 4 & 2 & 4 & \text{None} & \text{None} & \text{None} \\ \hline 5 & 1 & 5 & \text{None} & 10 & \text{None} \\ \hline \end{tabular} \][/tex]
Here's the detailed step-by-step breakdown:
1. Trial 1:
- Volume of [tex]\( CuSO_4 \)[/tex]: 5 mL
- Volume of [tex]\( Na_2S \)[/tex]: 1 mL
- Mass of Empty Test Tube: 4 g
- Mass of Test Tube and Precipitate: 3 g
- Mass of Precipitate: [tex]\( 3 \text{ g} - 4 \text{ g} = -1 \text{ g} \)[/tex] (indicating a missing or incorrect entry for "Mass of Test Tube and Precipitate")
2. Trial 2:
- Volume of [tex]\( CuSO_4 \)[/tex]: 4 mL
- Volume of [tex]\( Na_2S \)[/tex]: 2 mL
- Mass of Empty Test Tube: 8 g
- Mass of Test Tube and Precipitate: None (no data available)
- Mass of Precipitate: None (cannot be calculated without the mass of the test tube and precipitate)
3. Trial 3:
- Volume of [tex]\( CuSO_4 \)[/tex]: 3 mL
- Volume of [tex]\( Na_2S \)[/tex]: 3 mL
- Mass of Empty Test Tube: None (no data available)
- Mass of Test Tube and Precipitate: 5 g
- Mass of Precipitate: None (cannot be calculated without the mass of the empty test tube)
4. Trial 4:
- Volume of [tex]\( CuSO_4 \)[/tex]: 2 mL
- Volume of [tex]\( Na_2S \)[/tex]: 4 mL
- Mass of Empty Test Tube: None (no data available)
- Mass of Test Tube and Precipitate: None (no data available)
- Mass of Precipitate: None (cannot be calculated without both the mass of the empty test tube and the mass of the test tube and precipitate)
5. Trial 5:
- Volume of [tex]\( CuSO_4 \)[/tex]: 1 mL
- Volume of [tex]\( Na_2S \)[/tex]: 5 mL
- Mass of Empty Test Tube: None (no data available)
- Mass of Test Tube and Precipitate: 10 g
- Mass of Precipitate: None (cannot be calculated without the mass of the empty test tube)
We have now constructed the table with the available data.
[tex]\[ \begin{align*} (5, 1, 4, 3, -1) \\ (4, 2, 8, \text{None}, \text{None}) \\ (3, 3, \text{None}, 5, \text{None}) \\ (2, 4, \text{None}, \text{None}, \text{None}) \\ (1, 5, \text{None}, 10, \text{None}) \end{align*} \][/tex]
Now, let’s populate the table with this data. Note that "None" indicates missing values that could not be calculated.
[tex]\[ \begin{tabular}{|c|c|c|c|c|c|} \hline Trial & \begin{tabular}{c} Volume of \\ $CuSO_4(\text{mL})$ \end{tabular} & \begin{tabular}{c} Volume of \\ $Na_2S(\text{mL})$ \end{tabular} & \begin{tabular}{c} Mass of Empty \\ Test Tube (g) \end{tabular} & \begin{tabular}{c} Mass of Test Tube and \\ Precipitate (g) \end{tabular} & \begin{tabular}{c} Mass of \\ Precipitate (g) \end{tabular} \\ \hline 1 & 5 & 1 & 4 & 3 & -1 \\ \hline 2 & 4 & 2 & 8 & \text{None} & \text{None} \\ \hline 3 & 3 & 3 & \text{None} & 5 & \text{None} \\ \hline 4 & 2 & 4 & \text{None} & \text{None} & \text{None} \\ \hline 5 & 1 & 5 & \text{None} & 10 & \text{None} \\ \hline \end{tabular} \][/tex]
Here's the detailed step-by-step breakdown:
1. Trial 1:
- Volume of [tex]\( CuSO_4 \)[/tex]: 5 mL
- Volume of [tex]\( Na_2S \)[/tex]: 1 mL
- Mass of Empty Test Tube: 4 g
- Mass of Test Tube and Precipitate: 3 g
- Mass of Precipitate: [tex]\( 3 \text{ g} - 4 \text{ g} = -1 \text{ g} \)[/tex] (indicating a missing or incorrect entry for "Mass of Test Tube and Precipitate")
2. Trial 2:
- Volume of [tex]\( CuSO_4 \)[/tex]: 4 mL
- Volume of [tex]\( Na_2S \)[/tex]: 2 mL
- Mass of Empty Test Tube: 8 g
- Mass of Test Tube and Precipitate: None (no data available)
- Mass of Precipitate: None (cannot be calculated without the mass of the test tube and precipitate)
3. Trial 3:
- Volume of [tex]\( CuSO_4 \)[/tex]: 3 mL
- Volume of [tex]\( Na_2S \)[/tex]: 3 mL
- Mass of Empty Test Tube: None (no data available)
- Mass of Test Tube and Precipitate: 5 g
- Mass of Precipitate: None (cannot be calculated without the mass of the empty test tube)
4. Trial 4:
- Volume of [tex]\( CuSO_4 \)[/tex]: 2 mL
- Volume of [tex]\( Na_2S \)[/tex]: 4 mL
- Mass of Empty Test Tube: None (no data available)
- Mass of Test Tube and Precipitate: None (no data available)
- Mass of Precipitate: None (cannot be calculated without both the mass of the empty test tube and the mass of the test tube and precipitate)
5. Trial 5:
- Volume of [tex]\( CuSO_4 \)[/tex]: 1 mL
- Volume of [tex]\( Na_2S \)[/tex]: 5 mL
- Mass of Empty Test Tube: None (no data available)
- Mass of Test Tube and Precipitate: 10 g
- Mass of Precipitate: None (cannot be calculated without the mass of the empty test tube)
We have now constructed the table with the available data.
