Select the correct answer.

[tex]$\overline{JK}$[/tex] is dilated by a scale factor of [tex]$n$[/tex] with the origin as the center of dilation, resulting in the image [tex]$\overline{J^{\prime}K^{\prime}}$[/tex]. The slope of [tex]$\overline{JK}$[/tex] is [tex]$m$[/tex]. If the length of [tex]$\overline{JK}$[/tex] is [tex]$l$[/tex], what is the length of [tex]$\overline{J^{\prime}K^{\prime}}$[/tex]?

A. [tex]$m \times n \times l$[/tex]
B. [tex]$(m + n) \times l$[/tex]
C. [tex]$m \times l$[/tex]
D. [tex]$n \times l$[/tex]



Answer :

Let's solve the problem step-by-step to find the length of the dilated image [tex]\(\overline{J^{\prime} K^{\prime}}\)[/tex].

1. Understanding the Original Length:
- The given length of [tex]\(\overline{J K}\)[/tex] is denoted as [tex]\(l\)[/tex]. However, in the context of this problem, we see [tex]\(l\)[/tex] is not explicitly mentioned. Instead, the length of [tex]\(\overline{J K}\)[/tex] is usually taken as a unit length (for illustration purposes).

2. Dilation Transformation:
- The dilation transformation scales a figure by a given scale factor. Here, [tex]\(\overline{J K}\)[/tex] is being scaled by a factor of [tex]\(n\)[/tex] with the origin as the center of dilation.

3. Effect of Dilation on Length:
- When a line segment is dilated by a scale factor with respect to the origin, the length of the new line segment is the original length multiplied by the scale factor.

4. Calculating the New Length:
- If the original length of [tex]\(\overline{J K}\)[/tex] is 1 unit, the length of [tex]\(\overline{J^{\prime} K^{\prime}}\)[/tex] will be the original length multiplied by the scale factor [tex]\(n\)[/tex]:
[tex]\[ \text{Length of } \overline{J^{\prime} K^{\prime}} = 1 \times n = n \][/tex]

Therefore, the correct answer is:
[tex]\[ \boxed{n \times 1} \][/tex]

This corresponds to option D in the given choices. The length of [tex]\(\overline{J^{\prime} K^{\prime}}\)[/tex] is [tex]\(n\)[/tex].