Answer :

Let's break down the given expression step by step:

[tex]\[ \left[\frac{\left(x^2\right)^{-1} \cdot\left(x^{2^{-1}}\right) \cdot\left(x^{-2}\right)^{-1}}{\left(x^3\right)^{-1} \cdot\left(x^{3^{-1}}\right) \cdot\left(x^{-3}\right)^{-1}}\right]^6 \][/tex]

1. Simplify the Numerator:
- [tex]\(\left(x^2\right)^{-1}\)[/tex] can be simplified to [tex]\(x^{-2}\)[/tex].
- [tex]\(x^{2^{-1}}\)[/tex] is the same as [tex]\(x^{\frac{1}{2}}\)[/tex].
- [tex]\(\left(x^{-2}\right)^{-1}\)[/tex] can be simplified to [tex]\(x^2\)[/tex].

Putting it all together, the numerator becomes:
[tex]\[ x^{-2} \cdot x^{\frac{1}{2}} \cdot x^2 \][/tex]

Using the properties of exponents [tex]\(a^m \cdot a^n = a^{m+n}\)[/tex], we add the exponents:
[tex]\[ x^{-2 + \frac{1}{2} + 2} \][/tex]

Simplifying the exponents:
[tex]\[ -2 + 2 + \frac{1}{2} = \frac{1}{2} \][/tex]

So the numerator simplifies to:
[tex]\[ x^{\frac{1}{2}} \][/tex]

2. Simplify the Denominator:
- [tex]\(\left(x^3\right)^{-1}\)[/tex] can be simplified to [tex]\(x^{-3}\)[/tex].
- [tex]\(x^{3^{-1}}\)[/tex] is the same as [tex]\(x^{\frac{1}{3}}\)[/tex].
- [tex]\(\left(x^{-3}\right)^{-1}\)[/tex] can be simplified to [tex]\(x^3\)[/tex].

Putting it all together, the denominator becomes:
[tex]\[ x^{-3} \cdot x^{\frac{1}{3}} \cdot x^3 \][/tex]

Again using the properties of exponents:
[tex]\[ x^{-3 + \frac{1}{3} + 3} \][/tex]

Simplifying the exponents:
[tex]\[ -3 + 3 + \frac{1}{3} = \frac{1}{3} \][/tex]

So the denominator simplifies to:
[tex]\[ x^{\frac{1}{3}} \][/tex]

3. Forming the Fraction:
Now our expression becomes:
[tex]\[ \left[\frac{x^{\frac{1}{2}}}{x^{\frac{1}{3}}}\right]^6 \][/tex]

4. Simplify the Fraction:
By subtracting the exponents in the fraction:
[tex]\[ \frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6} \][/tex]

So, we have:
[tex]\[ x^{\frac{1}{6}} \][/tex]

5. Raise the Result to the Power of 6:
[tex]\[ \left(x^{\frac{1}{6}}\right)^6 \][/tex]

Using the property of exponents [tex]\((a^m)^n = a^{m \cdot n}\)[/tex]:
[tex]\[ x^{\frac{1}{6} \cdot 6} = x^1 = x \][/tex]

After simplifying the given expression step-by-step, we conclude that the expression simplifies to:

[tex]\[ \boxed{x} \][/tex]