Solve [tex]\tan^2(\theta)=1[/tex] on the interval [tex][0, \pi)[/tex].

The answers are [tex]A[/tex] and [tex]B[/tex] where [tex]0\ \textless \ A\ \textless \ B\ \textless \ \pi[/tex].

[tex]\[
\begin{array}{l}
A= \\
B=
\end{array}
\][/tex]

[tex]\square[/tex]



Answer :

To solve the equation [tex]\(\tan^2(\theta) = 1\)[/tex] on the interval [tex]\([0, \pi)\)[/tex], let's follow a step-by-step approach.

1. Understand the equation:
[tex]\[ \tan^2(\theta) = 1 \][/tex]
This implies:
[tex]\[ \tan(\theta) = \pm 1 \][/tex]

2. Find the angles where [tex]\(\tan(\theta) = 1\)[/tex]:
The tangent of an angle is [tex]\(1\)[/tex] at [tex]\(\theta\)[/tex] values of:
[tex]\[ \theta = \frac{\pi}{4} + k\pi, \quad k \in \mathbb{Z} \][/tex]
Within the interval [tex]\([0, \pi)\)[/tex], the only solution is:
[tex]\[ \theta = \frac{\pi}{4} \][/tex]

3. Find the angles where [tex]\(\tan(\theta) = -1\)[/tex]:
The tangent of an angle is [tex]\(-1\)[/tex] at [tex]\(\theta\)[/tex] values of:
[tex]\[ \theta = \frac{3\pi}{4} + k\pi, \quad k \in \mathbb{Z} \][/tex]
Within the interval [tex]\([0, \pi)\)[/tex], the only solution is:
[tex]\[ \theta = \frac{3\pi}{4} \][/tex]

4. Summarize the solutions:
Within the given interval [tex]\([0, \pi)\)[/tex], the solutions to the equation [tex]\(\tan^2(\theta) = 1\)[/tex] are:
[tex]\[ \theta = \frac{\pi}{4}, \quad \theta = \frac{3\pi}{4} \][/tex]

Thus, the answers are:
[tex]\[ A = \frac{\pi}{4} \approx 0.7854 \][/tex]
[tex]\[ B = \frac{3\pi}{4} \approx 2.3562 \][/tex]

Therefore, the solutions are:
[tex]\[ A = 0.7853981633974483 \][/tex]
[tex]\[ B = 2.356194490192345 \][/tex]
[tex]\(\boxed{0.7853981633974483}\)[/tex]
[tex]\(\boxed{2.356194490192345}\)[/tex]