Average Miles per Hour

\begin{tabular}{|c|c|c|c|c|c|}
\hline Make & [tex]$130-139.9$[/tex] & [tex]$140-149.9$[/tex] & [tex]$150-159.9$[/tex] & [tex]$160-169.9$[/tex] & [tex]$170-179.9$[/tex] \\
\hline Buick & [tex]$16.66 \bigcirc$[/tex] & 0 & 0 & 0 & 0 \\
\hline Chevrolet & [tex]$50.0$[/tex] & [tex]$62.5 \bigcirc$[/tex] & [tex]$66.68 \bigcirc$[/tex] & 75 & 100.0 \\
\hline Dodge & 0 & 25 & [tex]$0 \checkmark$[/tex] & 0 & [tex]$0 \checkmark$[/tex] \\
\hline Ford & 33.32 & 12.5 & 33.32 & 250 & 0 \\
\hline Total & [tex]$100 \bigcirc$[/tex] & 100 & [tex]$100 \bigcirc$[/tex] & 100 & 100 \\
\hline
\end{tabular}

What percentage of winning average speeds in the [tex]$160-169.9$[/tex] miles per hour range were Chevrolets?

[tex]$\square \%$[/tex]



Answer :

To determine the percentage of winning average speeds between 160-169.9 miles per hour that were achieved by Chevrolets, follow these steps:

1. Identify the number of wins by Chevrolets in the 160-169.9 mph range:
From the table, the number of wins by Chevrolets in the 160-169.9 mph range is 75.

2. Identify the total number of wins in the 160-169.9 mph range:
From the table, the total number of wins in the 160-169.9 mph range is 100.

3. Calculate the percentage of wins by Chevrolets:
To find the percentage, divide the number of wins by Chevrolets by the total number of wins in this range and then multiply by 100 to convert it to a percentage.

[tex]\[ \text{Percentage of Chevrolet wins} = \left(\frac{\text{Chevrolet wins}}{\text{Total wins}}\right) \times 100 \][/tex]

Substituting the given numbers:

[tex]\[ \text{Percentage of Chevrolet wins} = \left(\frac{75}{100}\right) \times 100 \][/tex]

4. Perform the calculation:

[tex]\[ \left(\frac{75}{100}\right) \times 100 = 75 \][/tex]

Therefore, the percentage of winning average speeds between 160-169.9 miles per hour that were Chevrolets is:
[tex]\[ 75 \% \][/tex]