Divide using synthetic division.

[tex]\[
\left(x^2+5x-2\right) \div (x+2)
\][/tex]

A. [tex]\(x+4\)[/tex]

B. [tex]\(x+3+\frac{8}{x+2}\)[/tex]

C. [tex]\(\frac{x+3}{x+2}\)[/tex]

D. [tex]\(x+3-\frac{8}{x+2}\)[/tex]



Answer :

Let's divide the polynomial [tex]\( x^2 + 5x - 2 \)[/tex] by [tex]\( x + 2 \)[/tex] using synthetic division step-by-step.

1. Synthetic Division Setup:
- Write down the coefficients of the polynomial [tex]\( x^2 + 5x - 2 \)[/tex]: [1, 5, -2]
- Identify the root of the divisor [tex]\( x + 2 \)[/tex]. Since [tex]\( x + 2 = 0 \)[/tex] implies [tex]\( x = -2 \)[/tex], we use [tex]\(-2\)[/tex] as the root for synthetic division.

2. Synthetic Division Process:
- Set up the synthetic division table:

```
-2 | 1 5 -2
```

- Bring down the leading coefficient (1) directly below the line.

```
-2 | 1 5 -2
----
1
```

- Multiply this number (1) by the root ([tex]\(-2\)[/tex]) and write the result under the next coefficient (5):

[tex]\(-2 \times 1 = -2\)[/tex]

```
-2 | 1 5 -2
----
1 -2
```

- Add the number above (5) to this product (-2) and write the sum below the line:

[tex]\(5 + (-2) = 3\)[/tex]

```
-2 | 1 5 -2
----
1 3
```

- Repeat the multiplication and addition steps for the remaining terms:

[tex]\(-2 \times 3 = -6\)[/tex]

```
-2 | 1 5 -2
----
1 3 -6
```

[tex]\(-2 + (-6) = -8\)[/tex]

3. Result Interpretation:
- The numbers below the line ([tex]\(1\)[/tex] and [tex]\(3\)[/tex]) represent the coefficients of the quotient polynomial.
- The last number ([tex]\(-8\)[/tex]) is the remainder.

[tex]\[ \frac{x^2 + 5x - 2}{x + 2} = x + 3 + \frac{-8}{x + 2} \][/tex]

4. Formatting the Quotient and Remainder:
- Insert the remainder term correctly:

[tex]\[ \frac{x^2 + 5x - 2}{x + 2} = x + 3 - \frac{8}{x + 2} \][/tex]

Thus, the correct multiple choice answer is:

D. [tex]\( x + 3 - \frac{8}{x + 2} \)[/tex]

So, the answer is D.