Solve [tex]\log_6 22 = \log_6 (5x - 8)[/tex] for [tex]x[/tex].

A. [tex]x = 6[/tex]
B. [tex]x = 0[/tex]
C. [tex]x = -11[/tex]
D. [tex]x = -14[/tex]



Answer :

To solve the equation [tex]\(\log_6 22 = \log_6 (5x - 8)\)[/tex] for [tex]\(x\)[/tex], follow these steps:

1. Understand the Logarithmic Equations:
Since the logarithms on both sides of the equation have the same base (base 6), we can equate the arguments of the logarithms directly. This means:
[tex]\[ 22 = 5x - 8 \][/tex]

2. Isolate [tex]\(5x\)[/tex]:
To solve for [tex]\(x\)[/tex], first isolate the term containing [tex]\(x\)[/tex]. Add 8 to both sides of the equation:
[tex]\[ 22 + 8 = 5x \][/tex]
Simplifying the left-hand side gives:
[tex]\[ 30 = 5x \][/tex]

3. Solve for [tex]\(x\)[/tex]:
Divide both sides of the equation by 5 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{30}{5} \][/tex]
Simplifying this gives:
[tex]\[ x = 6 \][/tex]

Thus, the solution to the equation [tex]\(\log_6 22 = \log_6 (5x - 8)\)[/tex] is:
[tex]\[ x = 6 \][/tex]

Hence, the correct answer is:
A. [tex]\(x = 6\)[/tex]