Select the best answer for the question.

What is the variation constant for an inverse squared relationship where [tex]$x=-4$[/tex] and [tex]$y=3$[/tex]?

A. -16
B. -48
C. 48
D. 16



Answer :

Alright, let's solve this step-by-step:

1. Understand the inverse squared relationship: In an inverse squared relationship, the relationship between [tex]\( y \)[/tex] and [tex]\( x \)[/tex] can be expressed as:
[tex]\[ y = \frac{k}{x^2} \][/tex]
where [tex]\( k \)[/tex] is the variation constant.

2. Identify the known values: We are given [tex]\( x = -4 \)[/tex] and [tex]\( y = 3 \)[/tex].

3. Substitute the known values into the equation: Plug [tex]\( x = -4 \)[/tex] and [tex]\( y = 3 \)[/tex] into the relationship:
[tex]\[ 3 = \frac{k}{(-4)^2} \][/tex]

4. Simplify the equation:
[tex]\[ 3 = \frac{k}{16} \][/tex]

5. Solve for [tex]\( k \)[/tex]:
[tex]\[ k = 3 \times 16 = 48 \][/tex]

The variation constant [tex]\( k \)[/tex] is [tex]\( 48 \)[/tex].

The best answer for the question, "What is the variation constant for an inverse squared relationship where [tex]\( x = -4 \)[/tex] and [tex]\( y = 3 \)[/tex]?" is:
C. 48