6. Describe the following variation: [tex]\frac{y}{x^2}=5[/tex]

A. [tex]y[/tex] varies inversely as [tex]x[/tex].

B. [tex]y[/tex] varies inversely as the square of [tex]x[/tex].

C. [tex]y[/tex] varies directly as the square of [tex]x[/tex].

D. [tex]y[/tex] varies directly as [tex]x[/tex].



Answer :

To describe the variation given by the equation [tex]\(\frac{y}{x^2} = 5\)[/tex], let's follow these steps:

1. Identify the Given Equation:

The equation provided is:
[tex]\[ \frac{y}{x^2} = 5 \][/tex]

2. Rearrange the Equation:

To understand how [tex]\(y\)[/tex] and [tex]\(x\)[/tex] are related, let's rearrange the equation to solve for [tex]\(y\)[/tex]:
[tex]\[ \frac{y}{x^2} = 5 \][/tex]
Multiply both sides of the equation by [tex]\(x^2\)[/tex]:
[tex]\[ y = 5x^2 \][/tex]

3. Understand the Relationship:

The rearranged equation shows that [tex]\(y\)[/tex] is equal to some constant (in this case, 5) multiplied by [tex]\(x\)[/tex] squared.

4. Determine the Type of Variation:

When we say that [tex]\(y\)[/tex] varies directly as another term, it means there is a constant [tex]\(k\)[/tex] such that [tex]\(y = k \times (\text{term})\)[/tex]. In this case:
[tex]\[ y = 5x^2 \][/tex]
Here, [tex]\(k\)[/tex], the constant of variation, is 5, and the term is [tex]\(x^2\)[/tex].

5. Conclude the Type of Variation:

Since [tex]\(y\)[/tex] is expressed as a constant times the square of [tex]\(x\)[/tex], we can conclude that [tex]\(y\)[/tex] varies directly as the square of [tex]\(x\)[/tex].

Therefore, the correct description of the variation given by the equation [tex]\(\frac{y}{x^2} = 5\)[/tex] is:

C. [tex]\(y\)[/tex] varies directly as the square of [tex]\(x\)[/tex].