Charlie wants to order lunch for his friends. He'll order 6 sandwiches and a [tex]$\$[/tex]2[tex]$ kid's meal for his little brother. Charlie has $[/tex]\[tex]$32$[/tex]. How much can he spend on each sandwich if they are all the same price?

Choose two answers: one for the inequality that models this situation and one for the correct answer.

A. Inequality: [tex]$2 x+6 \leq 32$[/tex]
B. Answer: [tex]$\$[/tex]13[tex]$ or less
C. Inequality: $[/tex]6 x+2 \leq 32[tex]$
D. Inequality: $[/tex]2 x+6<32[tex]$
E. Inequality: $[/tex]6 x+2 \geq 32[tex]$
F. Answer: $[/tex]\[tex]$5$[/tex] or less



Answer :

To solve the problem of determining how much Charlie can spend on each sandwich, let's break down the situation step by step.

1. Identify the Given Values:
- Charlie wants to buy 6 sandwiches.
- He also needs to buy a [tex]$2 kid's meal. - He has a total budget of $[/tex]32.

2. Set Up the Inequality:
- Let [tex]\( x \)[/tex] be the cost of each sandwich.
- So, the total cost for the sandwiches would be [tex]\( 6x \)[/tex].
- The total cost for both the sandwiches and the kid's meal is [tex]\( 6x + 2 \)[/tex].
- This total expenditure must be less than or equal to Charlie's budget of [tex]$32. - Hence, the inequality can be written as: \[ 6x + 2 \leq 32 \] 3. Solve the Inequality for \( x \): - Subtract 2 from both sides: \[ 6x + 2 - 2 \leq 32 - 2 \] \[ 6x \leq 30 \] - Divide both sides by 6: \[ \frac{6x}{6} \leq \frac{30}{6} \] \[ x \leq 5 \] 4. Interpret the Solution: - The maximum amount Charlie can spend on each sandwich is $[/tex]5.
- Therefore, the correct answers are:
[tex]\[ \textbf{C. Inequality: } 6x + 2 \leq 32 \][/tex]
[tex]\[ \textbf{F. Answer: } \$ 5 \text{ or less} \][/tex]

So, the correct choices that represent the inequality and the answer are:
C and F.