Select the correct answer.

The heights of the pine trees in a certain forest are normally distributed, with a mean of 86 feet and a standard deviation of 8 feet. Approximately what percentage of the pine trees in this forest are taller than 100 feet?

\begin{tabular}{|c|c|c|c|c|c|c|c|c|}
\hline \multicolumn{2}{|c|}{4} & \multicolumn{7}{|c|}{ Table shows values to the LEFT of the z-score } \\
\hline[tex]$z$[/tex] & 0.02 & 0.03 & 0.04 & 0.05 & 0.06 & 0.07 & 0.08 & 0.09 \\
\hline 1.6 & 0.94738 & 0.94845 & 0.94950 & 0.95053 & 0.95154 & 0.95254 & 0.95352 & 0.95449 \\
\hline 1.7 & 0.95728 & 0.95818 & 0.95907 & 0.95994 & 0.96080 & 0.96164 & 0.96246 & 0.96327 \\
\hline 1.8 & 0.96562 & 0.96638 & 0.96712 & 0.96784 & 0.96856 & 0.96926 & 0.96995 & 0.97062 \\
\hline 1.9 & 0.97257 & 0.97320 & 0.97381 & 0.97441 & 0.97500 & 0.97558 & 0.97615 & 0.97670 \\
\hline 2.0 & 0.97831 & 0.97882 & 0.97932 & 0.97982 & 0.98030 & 0.98077 & 0.98124 & 0.98169 \\
\hline-2.0 & 0.02169 & 0.02118 & 0.02068 & 0.02018 & 0.01970 & 0.01923 & 0.01876 & 0.01831 \\
\hline-1.9 & 0.02743 & 0.02680 & 0.02619 & 0.02559 & 0.02500 & 0.02442 & 0.02385 & 0.02330 \\
\hline-1.8 & 0.03438 & 0.03362 & 0.03288 & 0.03216 & 0.03144 & 0.03074 & 0.03005 & 0.02938 \\
\hline-1.7 & 0.04272 & 0.04182 & 0.04093 & 0.04006 & 0.03920 & 0.03836 & 0.03754 & 0.03673 \\
\hline-1.6 & 0.05262 & 0.05155 & 0.05050 & 0.04947 & 0.04846 & 0.04746 & 0.04648 & 0.04551 \\
\hline
\end{tabular}

A. [tex]$84 \%$[/tex]
B. [tex]$4 \%$[/tex]
C. [tex]$96 \%$[/tex]
D. [tex]$16 \%$[/tex]



Answer :

To find the percentage of pine trees in the forest that are taller than 100 feet, we need to follow these steps:

1. Determine the z-score: The z-score is a measure of how many standard deviations a value is from the mean. It is calculated using the formula:

[tex]\[ z = \frac{{X - \mu}}{{\sigma}} \][/tex]

where:
- [tex]\(X\)[/tex] is the value of interest (in this case, 100 feet),
- [tex]\(\mu\)[/tex] is the mean (86 feet),
- [tex]\(\sigma\)[/tex] is the standard deviation (8 feet).

Plugging in the values:

[tex]\[ z = \frac{{100 - 86}}{{8}} = \frac{14}{8} = 1.75 \][/tex]

2. Find the cumulative probability: The next step is to use the z-score to find the cumulative probability from the z-table. The z-score value we have is 1.75.

From the provided z-table, we find the corresponding cumulative probability:

[tex]\[ P(Z < 1.75) \approx 0.95994 \][/tex]

This means that approximately 95.994% of the trees are shorter than 100 feet.

3. Calculate the percentage of trees taller than 100 feet: The percentage of trees taller than 100 feet is the complement of the cumulative probability. This can be calculated as:

[tex]\[ P(X > 100) = 1 - P(Z < 1.75) \][/tex]

So:

[tex]\[ P(X > 100) = 1 - 0.95994 = 0.04006 \][/tex]

4. Convert the result to a percentage: To express the result as a percentage, multiply by 100:

[tex]\[ 0.04006 \times 100 \approx 4.006\% \][/tex]

Therefore, approximately [tex]\(4\%\)[/tex] of the pine trees in the forest are taller than 100 feet.

So, the correct answer is:

[tex]\[ \boxed{4 \%} \][/tex]