Let's solve this step-by-step.
We know that Leo had \[tex]$91, which is 7 times as much money as Alison had. We want to find the amount of money Alison had, denoted by \(x\).
The equation representing this situation is:
\[ 7x = 91 \]
To solve for \(x\), we need to isolate \(x\) on one side of the equation. We do this by dividing both sides of the equation by 7:
\[ x = \frac{91}{7} \]
When we perform this division, we get:
\[ x = 13 \]
Therefore, Alison had \$[/tex]13.
Looking at the solution methods provided:
A. [tex]\(\frac{x}{7} = 91\)[/tex]. Multiply both sides by 7. Alison had \[tex]$637. (Incorrect).
B. \(x - 7 = 91\). Add 7 to both sides. Alison had \$[/tex]98. (Incorrect).
C. [tex]\(x + 7 = 91\)[/tex]. Subtract 7 from both sides. Alison had \[tex]$84. (Incorrect).
D. \(7x = 91\). Divide both sides by 7. Alison had \$[/tex]13. (Correct).
So, the correct solution method is D.
