Find the mean of the scores to the nearest 10th from the table below:

\begin{tabular}{|c|c|}
\hline
Score & Number of Students \\
\hline
65 & 4 \\
\hline
70 & 8 \\
\hline
75 & 6 \\
\hline
80 & 3 \\
\hline
85 & 6 \\
\hline
90 & 6 \\
\hline
\end{tabular}

Answer Attempt 1 out of 2

[tex]$\square$[/tex]

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Answer :

Let's find the mean of the scores step-by-step:

1. Identify the data:

We have the following scores and the corresponding number of students:
- Score 65: 4 students
- Score 70: 8 students
- Score 75: 6 students
- Score 80: 3 students
- Score 85: 6 students
- Score 90: 6 students

2. Calculate the total number of students:

[tex]\[ \text{Total number of students} = 4 + 8 + 6 + 3 + 6 + 6 = 33 \][/tex]

3. Calculate the weighted sum of scores:

We need to multiply each score by the number of students who received that score and sum the results:
[tex]\[ \text{Weighted sum} = (65 \times 4) + (70 \times 8) + (75 \times 6) + (80 \times 3) + (85 \times 6) + (90 \times 6) \][/tex]
[tex]\[ = 260 + 560 + 450 + 240 + 510 + 540 = 2560 \][/tex]

4. Calculate the mean score:

The mean score is the weighted sum divided by the total number of students:
[tex]\[ \text{Mean score} = \frac{\text{Weighted sum}}{\text{Total number of students}} = \frac{2560}{33} \approx 77.57575757575758 \][/tex]

5. Round the mean score to the nearest 10th:

When rounded to the nearest 10th, the mean score is:
[tex]\[ \text{Mean score (rounded to the nearest 10th)} = 77.6 \][/tex]

Thus, the mean of the scores to the nearest 10th is:

[tex]\[ \boxed{77.6} \][/tex]