a) In an equation [tex]p = q[/tex], where [tex]p = (12x - 4) \frac{1}{3}[/tex] and [tex]q = 2 \left(4x - \frac{4}{3}\right)[/tex], the value of [tex]x[/tex] is:



Answer :

To solve for [tex]\( x \)[/tex] in the equation [tex]\( p = q \)[/tex] where [tex]\( p = \frac{12x - 4}{3} \)[/tex] and [tex]\( q = 2 \left(4x - \frac{4}{3} \right) \)[/tex], we follow these steps:

1. First, express both [tex]\( p \)[/tex] and [tex]\( q \)[/tex] in their simplified forms.

[tex]\[ p = \frac{12x - 4}{3} \][/tex]
[tex]\[ q = 2 \left(4x - \frac{4}{3} \right) \][/tex]

2. Distribute and simplify [tex]\( q \)[/tex]:

[tex]\[ q = 2 \left(4x - \frac{4}{3} \right) = 2 \cdot 4x - 2 \cdot \frac{4}{3} = 8x - \frac{8}{3} \][/tex]

So the equations are:

[tex]\[ p = \frac{12x - 4}{3} \][/tex]
[tex]\[ q = 8x - \frac{8}{3} \][/tex]

3. Set [tex]\( p \)[/tex] equal to [tex]\( q \)[/tex]:

[tex]\[ \frac{12x - 4}{3} = 8x - \frac{8}{3} \][/tex]

4. Clear the fractions by multiplying both sides by 3:

[tex]\[ 3 \cdot \frac{12x - 4}{3} = 3 \cdot \left(8x - \frac{8}{3}\right) \][/tex]

This simplifies to:

[tex]\[ 12x - 4 = 24x - 8 \][/tex]

5. Isolate [tex]\( x \)[/tex] by moving all terms involving [tex]\( x \)[/tex] to one side and the constants to the other:

[tex]\[ 12x - 24x = -8 + 4 \][/tex]
[tex]\[ -12x = -4 \][/tex]

6. Solve for [tex]\( x \)[/tex]:

[tex]\[ x = \frac{-4}{-12} = \frac{4}{12} = \frac{1}{3} \][/tex]

Therefore, the value of [tex]\( x \)[/tex] is:

[tex]\[ x = \frac{1}{3} \][/tex]

Or in decimal form:

[tex]\[ x \approx 0.333333333333333 \][/tex]