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A student earned grades of B, C, A, B, and D. These courses had the following corresponding numbers of credit hours: [tex]$4, 4, 4, 3, 2$[/tex]. The grading system assigns quality points to letter grades as follows: [tex]$A=4$[/tex], [tex]$B=3$[/tex], [tex]$C=2$[/tex], [tex]$D=1$[/tex], [tex]$F=0$[/tex].

Compute the grade-point average (GPA). If the dean's list requires a GPA of 3.00 or greater, did this student make the dean's list?

The student's GPA is [tex]$\square$[/tex] (Type an integer or decimal rounded to two decimal places as needed.)



Answer :

GinnyAnswer
To compute the student's grade-point average (GPA), we follow these steps:

1. Assign each letter grade its corresponding quality points using the given grading system:
- A = 4
- B = 3
- C = 2
- D = 1
- F = 0

The student's grades are B, C, A, B, and D. Therefore, their quality points are:
- B = 3
- C = 2
- A = 4
- B = 3
- D = 1

2. Multiply each grade's quality points by the course's credit hours to determine the total quality points for each course:
- For B (4 credit hours): [tex]\(3 \times 4 = 12\)[/tex]
- For C (4 credit hours): [tex]\(2 \times 4 = 8\)[/tex]
- For A (4 credit hours): [tex]\(4 \times 4 = 16\)[/tex]
- For B (3 credit hours): [tex]\(3 \times 3 = 9\)[/tex]
- For D (2 credit hours): [tex]\(1 \times 2 = 2\)[/tex]

3. Sum the total quality points from all courses:
[tex]\[ 12 + 8 + 16 + 9 + 2 = 47 \][/tex]

4. Sum the total number of credit hours:
[tex]\[ 4 + 4 + 4 + 3 + 2 = 17 \][/tex]

5. Calculate the GPA by dividing the total quality points by the total credit hours:
[tex]\[ \text{GPA} = \frac{47}{17} \approx 2.76 \][/tex]

6. Determine if the student made the dean's list:
The requirement for the dean's list is a GPA of 3.00 or greater. The student's GPA is 2.76, which is below the required 3.00.

Putting it all together:
- The student's GPA is approximately 2.76 (rounded to two decimal places).
- Since the GPA of 2.76 is less than 3.00, the student did not make the dean's list.

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