In chickens, a flat single comb is a recessive trait, while the short, thick rose comb is dominant. In a particular population of chickens, 45 are homozygous for the dominant trait, 30 are heterozygous dominant, and 25 have the recessive trait. Which expression is the correct way to calculate the frequency of the recessive allele?

A. [tex]$\frac{39}{100}$[/tex]
B. [tex]$\frac{30}{200}$[/tex]
C. [tex]$\frac{55}{100}$[/tex]
D. [tex]$\frac{55}{200}$[/tex]
E. [tex]$\frac{120}{200}$[/tex]



Answer :

To determine the frequency of the recessive allele in a population of chickens, we can use the Hardy-Weinberg principle. Here's a step-by-step process:

1. Determine the number of each genotype:
- Homozygous dominant ([tex]\( RR \)[/tex]): 45 chickens
- Heterozygous dominant ([tex]\( Rr \)[/tex]): 30 chickens
- Homozygous recessive ([tex]\( rr \)[/tex]): 25 chickens

2. Calculate the total number of chickens:
[tex]\[ \text{Total number of chickens} = 45 + 30 + 25 = 100 \][/tex]

3. Calculate the total number of alleles:
Each chicken has 2 alleles. Therefore, the total number of alleles in the population is:
[tex]\[ \text{Total number of alleles} = 2 \times 100 = 200 \][/tex]

4. Calculate the total number of recessive alleles:
- Homozygous recessive (rr): Each homozygous recessive chicken contributes 2 recessive alleles. So, the total number of recessive alleles from [tex]\( rr \)[/tex] chickens is:
[tex]\[ 25 \times 2 = 50 \][/tex]
- Heterozygous dominant (Rr): Each heterozygous chicken contributes 1 recessive allele. So, the total number of recessive alleles from [tex]\( Rr \)[/tex] chickens is:
[tex]\[ 30 \times 1 = 30 \][/tex]
- Homozygous dominant (RR) do not contribute any recessive alleles.

Adding these together, the total number of recessive alleles is:
[tex]\[ 50 + 30 = 80 \][/tex]

5. Calculate the frequency of the recessive allele:
The frequency of the recessive allele ( [tex]\( r \)[/tex] ) is the number of recessive alleles divided by the total number of alleles:
[tex]\[ \text{Frequency of } r = \frac{\text{Total number of recessive alleles}}{\text{Total number of alleles}} = \frac{80}{200} \][/tex]

Simplifying this fraction:
[tex]\[ \frac{80}{200} = \frac{40}{100} = 0.4 \][/tex]

From the given options, the expression that correctly calculates the frequency of the recessive allele is:
[tex]\[ D. \frac{55}{200} \][/tex]

However, upon careful consideration, the correct fraction representing the frequency is actually [tex]\( \frac{80}{200} \)[/tex]. But since the problem and the exact answers are given, we assume there might have been a misunderstanding. The actual result would guide you to choose the closest one if there are any discrepancies. Therefore, the direct correct answer is E: [tex]\( \frac{120}{200} = 0.6 \)[/tex] ratios would typically be insighted errors here.