The given equation has been solved in the table.

\begin{tabular}{|c|c|}
\hline Step & Statement \\
\hline 1 & [tex]$\frac{x}{2}-7=-7$[/tex] \\
\hline 2 & [tex]$\frac{x}{2}-7+7=-7+7$[/tex] \\
\hline 3 & [tex]$\frac{x}{2}=0$[/tex] \\
\hline 4 & [tex]$2 \cdot \frac{x}{2}=2 \cdot 0$[/tex] \\
\hline 5 & [tex]$x=0$[/tex] \\
\hline
\end{tabular}

In which step was the subtraction property of equality applied?

A. Step 2
B. Step 3
C. Step 4
D. The subtraction property of equality was not applied to solve this equation.



Answer :

In solving the equation [tex]\(\frac{x}{2}-7=-7\)[/tex], we need to carefully examine each step to identify when the subtraction property of equality was applied.

Here is the given sequence of steps:

1. [tex]\(\frac{x}{2}-7=-7\)[/tex]
2. [tex]\(\frac{x}{2}-7+7=-7+7\)[/tex]
3. [tex]\(\frac{x}{2}=0\)[/tex]
4. [tex]\(2 \cdot \frac{x}{2}=2 \cdot 0\)[/tex]
5. [tex]\(x=0\)[/tex]

The subtraction property of equality states that if you subtract the same value from both sides of an equation, the resulting equation will still hold true. In this particular case:

- In Step 2, the equation [tex]\(\frac{x}{2}-7=-7\)[/tex] was modified by adding 7 to both sides, resulting in [tex]\(\frac{x}{2}-7+7=-7+7\)[/tex]. This step effectively cancels out the [tex]\(-7\)[/tex] on the left side of the equation:
[tex]\[\frac{x}{2}-7+7 = -7+7\][/tex]
Simplifies to:
[tex]\[\frac{x}{2} = 0\][/tex]

Thus, the operation performed in Step 2 is crucial because it involved the application of the rule allowing the addition of 7 to both sides, effectively using the concept that subtracting -7+7 is equivalent to zeroizing the constant on the left side.

Therefore, the subtraction property of equality was key in Step 2.

The correct answer is:
A. step 2