To determine how many moles of FeO are produced when 8 moles of SO₂ are produced, we need to refer to the balanced chemical equation:
[tex]\[ 2 \text{CuFeS}_2 + 5 \text{O}_2 \rightarrow 2 \text{Cu} + 2 \text{FeO} + 4 \text{SO}_2 \][/tex]
From this balanced equation, we can see the stoichiometric relationship between FeO and SO₂. Specifically:
- 2 moles of FeO are produced for every 4 moles of SO₂.
To find the number of moles of FeO produced for 8 moles of SO₂, you can set up a proportion based on the stoichiometric coefficients:
[tex]\[
\frac{2 \text{ moles FeO}}{4 \text{ moles SO}_2} = \frac{x \text{ moles FeO}}{8 \text{ moles SO}_2}
\][/tex]
Now, solve for [tex]\( x \)[/tex], which represents the moles of FeO:
[tex]\[
\frac{2}{4} = \frac{x}{8}
\][/tex]
Cross-multiplying to solve for [tex]\( x \)[/tex]:
[tex]\[
2 \times 8 = 4 \times x
\][/tex]
[tex]\[
16 = 4x
\][/tex]
[tex]\[
x = \frac{16}{4}
\][/tex]
[tex]\[
x = 4
\][/tex]
Thus, [tex]\( x \)[/tex] is 4. Therefore, 4 moles of FeO are produced when 8 moles of SO₂ are produced.
The number of moles of FeO produced is:
[tex]\[ \boxed{4} \][/tex]
