Consider the electron configuration:

[tex]\[ \frac{\uparrow \downarrow}{1s} \][/tex]
[tex]\[ \frac{\uparrow \downarrow}{2s} \][/tex]
[tex]\[ \frac{\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow}{2p} \][/tex]
[tex]\[ \frac{\downarrow}{3s} \][/tex]

Which element has this electron configuration?

A. Astatine
B. Bromine
C. Chlorine
D. Fluorine



Answer :

Let's analyze the given electron configuration step-by-step to find the corresponding element:

1. 1s orbital:
- [tex]\(\frac{\uparrow \downarrow}{1s}\)[/tex]
- This signifies the 1s orbital, which can hold a maximum of 2 electrons, and it is fully occupied here.
- Electrons: 2

2. 2s orbital:
- [tex]\(\frac{\uparrow \downarrow}{2s}\)[/tex]
- This signifies the 2s orbital, which also can hold a maximum of 2 electrons, and it is fully occupied here.
- Electrons: 2

3. 2p orbital:
- [tex]\(\frac{\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow}{2p}\)[/tex]
- This signifies the 2p orbitals, which consist of three p-orbitals that can each hold up to 2 electrons, for a total of 6 electrons.
- Electrons: 6

4. 3s orbital:
- [tex]\(\frac{\downarrow}{3s}\)[/tex]
- This signifies the 3s orbital which can hold up to 2 electrons but only has 1 electron in it.
- Electrons: 1

Adding up all the electrons in these orbitals:

[tex]\[ 2 (\text{from 1s}) + 2 (\text{from 2s}) + 6 (\text{from 2p}) + 1 (\text{from 3s}) = 11 \][/tex]

Therefore, the total number of electrons is 11.

An atom with 11 electrons is Sodium, which corresponds to the atomic number 11. However, Sodium is not listed among the given options. This suggests a mistake in the provided list of options. According to the given electron configuration, the correct element should have an atomic number of 11, thus corresponding to Sodium (Na).